对静态 constexpr char[] 的未定义引用

问题描述

我想在我的班级中有一个 static const char 数组.GCC 抱怨并告诉我应该使用 constexpr，尽管现在它告诉我这是一个未定义的引用.如果我将数组设为非成员，则它会编译.这是怎么回事?

I want to have a static const char array in my class. GCC complained and told me I should use constexpr, although now it's telling me it's an undefined reference. If I make the array a non-member then it compiles. What is going on?

// .hpp
struct foo {
  void bar();
  static constexpr char baz[] = "quz";
};

// .cpp
void foo::bar() {
  std::string str(baz); // undefined reference to baz
}

推荐答案

添加到您的 cpp 文件:

Add to your cpp file:

constexpr char foo::baz[];

原因:您必须提供静态成员的定义以及声明.声明和初始化器在类定义中，但成员定义必须分开.

Reason: You have to provide the definition of the static member as well as the declaration. The declaration and the initializer go inside the class definition, but the member definition has to be separate.

这篇关于对静态 constexpr char[] 的未定义引用的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持跟版网！