C/C99/C++/C++x/GNU C/GNU C99 中枚举的签名

Signedness of enum in C/C99/C++/C++x/GNU C/GNU C99(C/C99/C++/C++x/GNU C/GNU C99 中枚举的签名)

问题描述

enum 类型是有符号的还是无符号的?枚举的符号性是否不同:C/C99/ANSI C/C++/C++x/GNU C/GNU C99?

Is the enum type signed or unsigned? Does the signedness of enums differ between: C/C99/ANSI C/C++/C++x/GNU C/ GNU C99?

谢谢

推荐答案

枚举保证由整数表示，但实际类型(及其符号)取决于实现.

An enum is guaranteed to be represented by an integer, but the actual type (and its signedness) is implementation-dependent.

您可以通过为枚举器之一赋予负值来强制枚举由有符号类型表示:

You can force an enumeration to be represented by a signed type by giving one of the enumerators a negative value:

enum SignedEnum { a = -1 };

在 C++0x 中，可以显式指定枚举的基础类型:

In C++0x, the underlying type of an enumeration can be explicitly specified:

enum ShortEnum : short { a };

(C++0x 还增加了对作用域枚举的支持)

(C++0x also adds support for scoped enumerations)

为了完整起见，我将在 The C Programming Language, 2nd ed. 中添加，枚举器被指定为具有 int 类型(第 215 页).K&R 不是 C 标准，所以它不是 ISO C 编译器的规范，但它确实早于 ISO C 标准，所以它至少从历史的角度来看很有趣.

For completeness, I'll add that in The C Programming Language, 2nd ed., enumerators are specified as having type int (p. 215). K&R is not the C standard, so that's not normative for ISO C compilers, but it does predate the ISO C standard, so it's at least interesting from a historical standpoint.

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