问题描述
假设我有一个模板，它由一个类类型和许多参数类型参数化.匹配这些类型的一组参数存储在一个元组中.如何将这些传递给类类型的构造函数?
Suppose I have a template which is parametrized by a class type and a number of argument types. a set of arguments matching these types are stored in a tuple. How can one pass these to a constructor of the class type?
几乎在 C++11 代码中:
In almost C++11 code:
template<typename T, typename... Args>
struct foo {
tuple<Args...> args;
T gen() { return T(get<0>(args), get<1>(args), ...); }
};
如何在不固定长度的情况下填充构造函数调用中的...?
How can the ... in the constructor call be filled without fixing the length?
我想我可以想出一些复杂的递归模板调用机制来做到这一点，但我不敢相信我是第一个想要这个的人，所以我想会有现成的解决方案这在那里，甚至可能在标准库中.
I guess I could come up with some complicated mechanism of recursive template calls which does this, but I can't believe that I'm the first to want this, so I guess there will be ready-to-use solutions to this out there, perhaps even in the standard libraries.
推荐答案
C++17 有 std::make_from_tuple 为此:
C++17 has std::make_from_tuple for this:
template <typename T, typename... Args>
struct foo
{
std::tuple<Args...> args;
T gen() { return std::make_from_tuple<T>(args); }
};
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