如何最优雅地获取 std::vector 缓冲区的地址开始?

问题描述

我想使用 std::vector 来动态分配内存.场景是:

I want to use std::vector for dynamically allocating memory. The scenario is:

int neededLength = computeLength(); // some logic here

// this will allocate the buffer     
std::vector<TCHAR> buffer( neededLength );

// call a function that accepts TCHAR* and the number of elements
callFunction( &(buffer[0]), buffer.size() );

上面的代码有效，但是这个 &(buffer[0]) 看起来很难看.有没有更优雅的方法来实现相同的目标?

The code above works, but this &(buffer[0]) looks ugly. Is there a more elegant way to achieve the same?

推荐答案

好吧，你可以删除一组括号:

Well, you can remove one set of parens:

&buffer[0]

但这是常见的、惯用的方式.如果它真的冒犯了您，我想您可以使用模板 - 类似于:

but that is the common, idiomatic way of doing it. If it really offends you, I suppose you could use a template - something like:

template <typename T> 
T * StartOf( std::vector <T> & v ) {
    return &v[0];
}

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