错误:用“{...}"初始化；预期聚合对象 - C++

问题描述

struct test
{
    unsigned int test1;
    unsigned char test2[4096];
    unsigned int test3;
} foo

struct foobar
{
unsigned char data[4096];
}

如果我想访问结构体，我会说 foo.test1、foo.test2[4096] 等等.但是，当我希望以下列方式返回 foo.test2 中存在的数据时

if i want to access the struct, i say foo.test1, foo.test2[4096], etc.. however, when I wish to return the data present in foo.test2 in the following manner

pac.datafoo = foo.test2[4096];

unsigned char data[4096] =  pac.datafoo;

这是我得到的错误:

error: initialization with "{...}" expected for aggregate object

我做错了什么?

推荐答案

需要学习数组的初始化方法.它不是简单地分配为单个变量.

You need to learn the array initialization method. It's NOT simply assigned as the single variable.

一些例子:

int arrayone[3] = {0}; // assign all items with 0

int arraytwo[3] = {1, 2, 3 }; // assign each item with 1, 2 and 3

int arraythree[3]; // assign arraythree with arraytwo
for (int i = 0; i < 3; ++i) {
    arraythree[i] = arraytwo[i];
}

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