C++ 结构的函数

问题描述

通常我们可以为 C++ 结构定义一个变量，如

Usually we can define a variable for a C++ struct, as in

struct foo {
  int bar;
};

我们也可以为结构定义函数吗?我们将如何使用这些功能?

Can we also define functions for a struct? How would we use those functions?

推荐答案

是的，struct 与 class 相同，除了默认的访问级别(member-wise和继承方面).(以及 class 与模板一起使用时的额外含义)

Yes, a struct is identical to a class except for the default access level (member-wise and inheritance-wise). (and the extra meaning class carries when used with a template)

一个类支持的每一个功能都因此得到一个结构的支持.您使用的方法与在类中使用方法相同.

Every functionality supported by a class is consequently supported by a struct. You'd use methods the same as you'd use them for a class.

struct foo {
  int bar;
  foo() : bar(3) {}   //look, a constructor
  int getBar() 
  { 
    return bar; 
  }
};

foo f;
int y = f.getBar(); // y is 3

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