本文介绍了当前日期和时间作为字符串的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着跟版网的小编来一起学习吧!
问题描述
我编写了一个函数来获取当前日期和时间的格式:DD-MM-YYYY HH:MM:SS.它有效,但让我们说,它非常丑陋.我怎样才能做完全相同的事情但更简单?
I wrote a function to get a current date and time in format: DD-MM-YYYY HH:MM:SS. It works but let's say, its pretty ugly. How can I do exactly the same thing but simpler?
string currentDateToString()
{
time_t now = time(0);
tm *ltm = localtime(&now);
string dateString = "", tmp = "";
tmp = numToString(ltm->tm_mday);
if (tmp.length() == 1)
tmp.insert(0, "0");
dateString += tmp;
dateString += "-";
tmp = numToString(1 + ltm->tm_mon);
if (tmp.length() == 1)
tmp.insert(0, "0");
dateString += tmp;
dateString += "-";
tmp = numToString(1900 + ltm->tm_year);
dateString += tmp;
dateString += " ";
tmp = numToString(ltm->tm_hour);
if (tmp.length() == 1)
tmp.insert(0, "0");
dateString += tmp;
dateString += ":";
tmp = numToString(1 + ltm->tm_min);
if (tmp.length() == 1)
tmp.insert(0, "0");
dateString += tmp;
dateString += ":";
tmp = numToString(1 + ltm->tm_sec);
if (tmp.length() == 1)
tmp.insert(0, "0");
dateString += tmp;
return dateString;
}
推荐答案
Non C++11 solution: with the header, you can use strftime.确保您的缓冲区足够大,您不希望它溢出并在以后造成严重破坏.
Non C++11 solution: With the <ctime> header, you could use strftime. Make sure your buffer is large enough, you wouldn't want to overrun it and wreak havoc later.
#include <iostream>
#include <ctime>
int main ()
{
time_t rawtime;
struct tm * timeinfo;
char buffer[80];
time (&rawtime);
timeinfo = localtime(&rawtime);
strftime(buffer,sizeof(buffer),"%d-%m-%Y %H:%M:%S",timeinfo);
std::string str(buffer);
std::cout << str;
return 0;
}
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