如何将 unique_ptr 捕获到 lambda 表达式中?

问题描述

我尝试了以下方法:

std::function<void ()> getAction(std::unique_ptr<MyClass> &&psomething){
    //The caller given ownership of psomething
    return [psomething](){ 
        psomething->do_some_thing();
        //psomething is expected to be released after this point
    };
}

但它不编译.有什么想法吗?

But it does not compile. Any ideas?

更新:

建议，需要一些新语法来明确指定我们需要将所有权转移到 lambda，我现在正在考虑以下语法:

AS suggested, some new syntax is required to explicitly specify we need to transfer the ownership to the lambda, I am now thinking about the following syntax:

std::function<void ()> getAction(std::unique_ptr<MyClass> psomething){
    //The caller given ownership of psomething
    return [auto psomething=move(psomething)](){ 
        psomething->do_some_thing();
        //psomething is expected to be released after this point
    };
}

它会是一个好的候选人吗?

Would it be a good candidate?

更新 1:

我将展示我对 move 和 copy 的实现如下:

I will show my implementation of move and copy as following:

template<typename T>
T copy(const T &t) {
    return t;
}

//process lvalue references
template<typename T>
T move(T &t) {
    return std::move(t);
}

class A{/*...*
The End