尝试解码不在 base64 字符集中的值

问题描述

我使用以下代码片段使用 Boost C++ 库对字符串进行 base64 编码和解码.

I am using the following code snippet to base64 encode and decode a string using Boost C++ library.

//Base64 Encode Implementation using Boost C++ library
const std::string base64_padding[] = {"", "=", "=="};

std::string X_Privet_Token_Generator::base64_encode(const std::string & s)
{
  namespace bai = boost::archive::iterators;

  std::stringstream os;

  // convert binary values to base64 characters
  typedef bai::base64_from_binary

  // retrieve 6 bit integers from a sequence of 8 bit bytes
  <bai::transform_width<const char *, 6, 8> > base64_enc; // compose all the above operations in to a new iterator

  std::copy(base64_enc(s.c_str()), base64_enc(s.c_str() + s.size()), std::ostream_iterator<char>(os));

  os << base64_padding[s.size() % 3];
  return os.str();
}

std::string X_Privet_Token_Generator::base64_decode(std::string & s)
{
  namespace bai = boost::archive::iterators;

  std::stringstream os;

  // convert binary values to base64 characters
  typedef bai::binary_from_base64

  <bai::transform_width<const char *, 8, 6> > base64_dec;

  unsigned int size = s.size();

  // Remove the padding characters, cf.
  if (size && s[size - 1] == '=')
  {
      --size;
      if (size && s[size - 1] == '=')
          --size;
  }

  if (size == 0)
      return std::string();

  LOGINFO("Hash decoded token : %s", s.c_str());
  std::copy(base64_dec(s.data()), base64_dec(s.data() + size), std::ostream_iterator<char>(os));
  std::cout<< os.str();
  return os.str();
}

编码效果很好，但是在解码时出现以下错误:

Encoding works well, however, while decoding I get the following error:

在抛出 boost::archive::iterators::dataflow_exception

what():尝试解码不在 base64 字符集中的值

what(): attempt to decode a value not in base64 char set

是否是导致此问题的填充字符之一?我在这里遗漏了什么吗?

Is it one of the padded characters that is causing this issue? Am I missing something here?

推荐答案

填充字符 '=' 是 b64 编码数据的一部分，在解码之前不应删除.b64 以 4 个字符的块进行编码，我怀疑在解码时它会在字符串末尾读取 '' 而不是预期的 '='.

The padding characters '=' are part of the b64 encoded data and should not be removed before decoding. b64 is encoded in blocks of 4 character, I suspect that while decoding it reads a '' instead of an expected '=' at the end of the string.

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