问题描述
如果文本文件不存在，我只是想创建一个文本文件，而且我似乎无法让 fstream 做到这一点.
I'm simply trying to create a text file if it does not exist and I can't seem to get fstream to do this.
#include <fstream>
using std::fstream;
int main(int argc, char *argv[]) {
fstream file;
file.open("test.txt");
file << "test";
file.close();
}
我是否需要在 open() 函数中指定任何内容才能让它创建文件?我已经读到你不能指定 ios::in ，因为这会期望一个已经存在的文件在那里，但我不确定是否需要为一个文件指定其他参数不存在.
Do I need to specify anything in the open() function in order to get it to create the file? I've read that you can't specify ios::in as that will expect an already existing file to be there, but I'm unsure if other parameters need to be specified for a file that does not already exist.
推荐答案
你应该像这样添加 fstream::out 到 open 方法:
You should add fstream::out to open method like this:
file.open("test.txt",fstream::out);
有关 fstream 标志的更多信息，请查看此链接:http://www.cplusplus.com/reference/fstream/fstream/open/
More information about fstream flags, check out this link: http://www.cplusplus.com/reference/fstream/fstream/open/
这篇关于fstream 不会创建文件的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持跟版网！