强制 GCC 将 .cpp 文件编译为 C

问题描述

我有一个外部提供的 .cpp 文件.它是 C 兼容代码和一些 C++ 的混合体.C++ 代码只是对 C 的封装，以利用 C++ 的特性.

I have an externally provided .cpp file. It is a mixture of C compatible code and a bit of C++ as well. The C++ code is just a wrapper around the C to take advantage of C++ features.

它使用 #ifdef __cplusplus 宏来保护 C++ 代码，这很棒.不幸的是，如果我尝试使用 GCC 进行编译，由于文件结尾，它会将其视为 C++.我知道 gcc 和 g++ 之间的区别 - 我不想编译为 C++.

It uses #ifdef __cplusplus macros to protect the C++ code, which is great. Unfortunately, if I try to compile using GCC, it treats it as C++ because of the file ending. I'm aware of the differences between gcc and g++ - I don't want to compile as C++.

有什么办法可以强制 GCC 将此文件视为 C 文件?我试过使用例如--std=c99，但这会正确地产生 C99 对 C++ 无效的错误.

Is there any way I can force GCC to treat this file as a C file? I've tried using e.g. --std=c99, but this correctly produces the error that C99 isn't valid for C++.

将文件重命名为 .c 是可行的，但如果可能的话，我想避免这种情况，因为它是外部提供的，最好将其保留为原始副本.

Renaming the file to .c works, but I'd like to avoid this if possible because it's externally provided and it'd be nice for it to remain as a pristine copy.

推荐答案

gcc 的 -x 选项允许您指定其后的所有输入文件的语言:

The -x option for gcc lets you specify the language of all input files following it:

$ gcc -x c your-file-name.cpp

如果你只想对那个文件进行特殊处理，你可以使用 -x none 来关闭特殊处理:

If you only want to special-case that one file, you can use -x none to shut off the special treatment:

$ gcc -x c your-filename.cpp -x none other-file-name.cpp

(your-filename.cpp 将编译为 C，而 other-file-name.cpp 将使用扩展名并编译为 C++)

(your-filename.cpp will be compiled as C, while other-file-name.cpp will use the extension and compile as C++)

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