从 C++ 函数返回对象的正确方法是什么?

问题描述

我很困惑:

• 返回一个对象(但是该对象是从函数中的局部变量复制而来的，这会消耗内存)
• 返回一个指针(但是你必须记住在调用代码中删除它，这很奇怪)
• 返回一个引用(但这是不可能的，因为这将是对函数局部变量的引用，一旦函数结束，它就会被删除)

• returning an object (but then the object is copied from the local variable in the function, which consumes memory)
• returning a pointer (but then you have to remember to delete it, in the calling code, which is weird)
• returning a reference (but this is not possible because this would be a reference to a local variable of the function, which would be deleted as soon as the function ends)

我正在寻找在基本 C++ 中从 C++ 函数返回对象的正确方法(没有库处理指针和自动释放内存).我想知道这应该怎么做.

I am looking for the proper way to return an object from a C++ function, in basic C++ (no library handling pointers and freeing memory automatically). I want to know how this is supposed to be done.

谢谢

推荐答案

现代编译器通常实现 (命名)返回值优化，通过它您引用的副本(并且在逻辑上期望)没有完成.

Modern compilers typically implement the (Named) Return Value Optimization, by which the copy you reference (and would logically expect) is not done.

从 Visual Studio 2005 (VC++ 8.0) 开始，我就不再考虑返回对象.

Ever since Visual Studio 2005 (VC++ 8.0) I don't think twice about returning objects.

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