如何使用 NewtonSoft 更新 JSON 对象的属性

I would like to update the option property to "Male" if the value is "ML" and "Female" if the value is "FM".

我已经到了这一点，但不确定如何继续:

I have got to this point, but am unsure how to proceed:

JArray contentobject = (JArray)JsonConvert.DeserializeObject(contentJSON);  
JObject voicgObj = contentobject.Children().FirstOrDefault(ce =>   ce["code"].ToString() == "GENDER") as JObject;
JProperty voicgProp = voicgObj.Property("value");

我不知道如何访问 option，它是 value 的子项.

I don't know how to get to the option which is a child of value.

提前致谢.任何指针都会很棒.

Thanks in advance. Any pointers would be great.

推荐答案

可以通过属性作为键来访问对象:

You can access the object by using properties as keys:

JObject obj = JObject.Parse(json);
string gender = (string)obj["value"]["option"];

对于您的示例，请尝试:

For your example, try:

JObject obj = JObject.Parse(json);
var val = obj["value"];
string option = (string)val["option"];

if (option == "ML")
   val["option"] = "Male";

if (option == "FM")
   val["option"] = "Female";

string result = obj.ToString();

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