需要 ClassInterfaceType.None 吗?

[ComVisible(true)] 是 COM 可见性的必要条件吗?

Is [ComVisible(true)] a must for COM visibility?

推荐答案

参见 这篇博文 用于扩展第一个问题.关键是，除非您指定 ClassInterfaceType.None，否则会生成一个额外的接口，如果您更改方法的顺序、更改它们的签名或删除其中一些，这可能会导致二进制兼容性问题.一个更好的选择是显式定义一个接口并从它继承你的类，指定 ClassInterfaceType.None.

See this blog post for the expanation of the first problem. The point is that unless you specify ClassInterfaceType.None an extra interface is generated and this can cause problems with binary compatibility if you alter the order of methods, change their signatures or remove some of them. A much better alternative is to explicitly define an interface and inherit your class from it specifying ClassInterfaceType.None.

ComVisible(true) 对于 COM 可见性不是必须的.默认情况下，公共类的所有公共方法和所有公共类都是 COM 可见的，所有其他实体都是 COM 不可见的.如果你需要改变这个，你可以使用 ComVisible 属性，通常是为了减少 COM 可见类的数量，因为每个 COM 可见类的注册表条目和类型库条目都会生成，这会导致不必要的注册表污染并膨胀类型库.IMO 最好用 ComVisible 明确标记所有公共实体.

ComVisible(true) is not a must for COM visibility. By default all public methods of public classes and all public classes are COM visible, all other entities are not COM visible. If you need to alter this you use ComVisible attribute, usually to decrease the amount of COM visible classes since for every COM visible class registry entries and type library entries are generated and this causes unnecessary registry pollution and inflates the type library. IMO it's a good idea to explicitly mark all public entities with ComVisible.

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