如何在 SQL Server 的 INSERT 存储过程中生成唯一的增量员工代码(模式:E0001, E0002, E0

问题描述

我想在 INSERT 存储过程中插入单个记录时生成唯一的员工代码.

I want to generate unique employee code at a time of inserting a single record in INSERT stored procedure.

第一次程序调用将生成员工代码为 E0001，第二次调用将生成 E0002，...

First-time procedure call will generate employee code as E0001, the second call will generate E0002, ...

预期的输出应该是这样的，

The expected output should look like,

EmployeeCode    EmployeeName
-------------------------------
E0001           A
E0002           B
E0003           C
E0004           D
E0005           E
  '             '
  '             '
  '             '
E9999           ZZZ

推荐答案

您可以在默认情况下将序列值嵌入到自定义格式的字符串中，并使用检查约束强制执行它.像这样:

You can embed a sequence value into a custom-formatted string in a default, and enforce it with a check constraint. Like this:

--drop table if exists Employee
--drop sequence seq_Employee
--go

create sequence seq_Employee
start with 1
increment by 1    
go

CREATE TABLE Employee
(
    EmployeeCode char(5) PRIMARY KEY 
        default 'E' + format((next value for seq_Employee),'0000' )
        check (EmployeeCode like 'E[0-9][0-9][0-9][0-9]'),
    EmployeeName VARCHAR(50) NOT NULL
)    
go

insert into Employee(EmployeeName)
values ('A'),('B'),('C'),('D'),('E')

select *
from Employee

输出

EmployeeCode EmployeeName
------------ --------------------------------------------------
E0001        A
E0002        B
E0003        C
E0004        D
E0005        E

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