我看到很多关于这个主题的话题，但我一直没有成功理解如何去做.
例如，如果我有这张表:
+------+-------+-------+|身份证 |姓名 |类 |+------+-------+-------+|5 |测试 |一 ||10 |测试2 |一 ||12 |测试5 |一 ||7 |测试6 |二 |+------+-------+-------+我只想显示一"类中的 X 个随机行，我该怎么做?
注意:这是一张大桌子，所以我不想使用ORDER BY RAND.
正如您所知，大多数人推荐的 ORDER BY RAND() 解决方案不能扩展到大型表.
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SET @r := (SELECT FLOOR(RAND() * (SELECT COUNT(*) FROM mytable)));SET @sql := CONCAT('SELECT * FROM mytable LIMIT 1 OFFSET', @r);从@sql 准备 stmt1;执行 stmt1;我在我的书中介绍了这个和其他解决方案，SQL 反模式:避免陷阱数据库编程.
<小时>如果你想用 PHP 做到这一点，你可以这样做(未测试):
begin_transaction();$result = $mysqli->query("SELECT COUNT(*) FROM mytable")$row = $result->fetch_row();$count = $row[0];$offset = mt_rand(0, $count);$result = $mysqli->query("SELECT * FROM mytable LIMIT 1 OFFSET $offset");...$mysqli->commit();I saw many topics about this subject and I have been unsuccessful in understanding how to do it.
For example, if I have this table:
+------+-------+-------+
| id | name | class |
+------+-------+-------+
| 5 | test | one |
| 10 | test2 | one |
| 12 | test5 | one |
| 7 | test6 | two |
+------+-------+-------+
and I want to show only X random rows from class "one", how can I do that?
NOTE: it's a big table, so I don't want to use ORDER BY RAND.
The ORDER BY RAND() solution that most people recommend doesn't scale to large tables, as you already know.
SET @r := (SELECT FLOOR(RAND() * (SELECT COUNT(*) FROM mytable)));
SET @sql := CONCAT('SELECT * FROM mytable LIMIT 1 OFFSET ', @r);
PREPARE stmt1 FROM @sql;
EXECUTE stmt1;
I cover this and other solutions in my book, SQL Antipatterns: Avoiding the Pitfalls of Database Programming.
If you want to do this with PHP, you could do something like this (not tested):
<?php
$mysqli->begin_transaction();
$result = $mysqli->query("SELECT COUNT(*) FROM mytable")
$row = $result->fetch_row();
$count = $row[0];
$offset = mt_rand(0, $count);
$result = $mysqli->query("SELECT * FROM mytable LIMIT 1 OFFSET $offset");
...
$mysqli->commit();
这篇关于使用 MySQL 选择随机行的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持跟版网！