SQL查询显示最近的日期?

问题描述

我想弄清楚如何编写一个 MySQL 查询，该查询将返回最接近日期的 3 个事件.

I'm trying to figure out how to write a MySQL query that will return the closest 3 events in terms of date.

这是我的桌子:

EVENT_ID    EVENT_NAME     EVENT_START_DATE(DATETIME)
1           test           2011-06-01 23:00:00
2           test2          2011-06-03 23:00:00
3           test3          2011-07-01 23:00:00
4           test4          2011-08-09 23:00:00
5           test5          2011-06-02 23:00:00
6           test6          2011-04-20 23:00:00

因此查询结果应该是 ID 的 1,2,5，因为它们与当前日期相比最接近发生..

So the query result should be for ID's 1,2,5 as they are the closest to occur in comparison to the current date..

查询应该只找到未来的事件.

query should find only future events.

推荐答案

SELECT event_id 
FROM Table 
ORDER BY ABS( DATEDIFF( EVENT_START_DATE, NOW() ) ) 
LIMIT 3

ABS() 表示 1 天前的事件与未来 1 天的事件一样接近.如果您只想要尚未发生的事件，请执行

The ABS() means that an event 1 day ago is just as close as an event 1 day in the future. If you only want events that haven't happened yet, do

SELECT event_id 
FROM Table 
WHERE EVENT_START_DATE > NOW() 
ORDER BY EVENT_START_DATE 
LIMIT 3 

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