如何在SQL中返回每个组的增量组号

How to return a incremental group number per group in SQL(如何在SQL中返回每个组的增量组号)

问题描述

我想在 SQL 中创建一个数据查询，以递增地编号行组，在公共日期时间分组，并在下一个日期时间保持组号"递增，依此类推.正如我在使用 partition by 语句时所看到的那样，这些组号"不得为每个组重置.这是我的示例数据:

I would like create a data query in SQL to incrementally number groups of rows, grouped on a common datetime and keep the "group numbers" incrementing on the next datetime and so on. These "group numbers" must not reset for each group as I have seen when using the partition by statement. Here is my sample data:

ts_DateTime          |ID   |Value|RowFilter|RequiredResult
--------------------------
2013/01/09 09:23:16  |8009 |0    |1        |1
2013/01/09 09:23:16  |8010 |0    |2        |1
2013/01/09 09:23:16  |8026 |0    |3        |1

2013/01/09 09:23:22  |8026 |0    |1        |2

2013/01/09 09:23:28  |8009 |0    |1        |3
2013/01/09 09:23:28  |8010 |0    |2        |3
2013/01/09 09:23:28  |8026 |0    |3        |3

2013/01/09 09:27:03  |8009 |0    |1        |4
2013/01/09 09:27:03  |8010 |0    |2        |4
2013/01/09 09:27:03  |8026 |0    |3        |4

2013/01/09 09:27:09  |8009 |0    |1        |5
2013/01/09 09:27:09  |8010 |0    |2        |5
2013/01/09 09:27:09  |8026 |0    |3        |5

2013/01/09 09:27:15  |8009 |0    |1        |6
2013/01/09 09:27:15  |8010 |0    |2        |6
2013/01/09 09:27:15  |8026 |0    |3        |6

我用来获得这些结果的查询是:

The query I am using to get these results is :

select hl.ts_DateTime,  hl.Tagname as [ID],  hl.TagValue as [Value],
ROW_NUMBER() OVER (PARTITION BY hl.ts_datetime ORDER BY hl.tagname) AS RowFilter
from Table1 hl

所以基本上，查看 RowFilter 列，我得到每个 ts_DateTime 分区的唯一 ROW 编号.我真正需要的是，对于每个 ts_DateTime 分区，RowFilter 列应该看起来像所需的结果列.

So basically, looking at the RowFilter column, I am getting a unique ROW number per ts_DateTime partition. What I actually need is that for each ts_DateTime partition the RowFilter column should look like the Required result column.

推荐答案

你不应该使用 ROW_NUMBER(),

• 改用DENSE_RANK()
• 删除PARTITION BY

查询，

SELECT hl.ts_DateTime,  
       hl.Tagname as [ID],  
       hl.TagValue as [Value],
       DENSE_RANK() OVER (ORDER BY ts_datetime) AS RowFilter
FROM   Table1 hl 
ORDER  BY RowFilter

• SQLFiddle 演示

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