Understanding Oracle aliasing - why isn#39;t an alias not recognized in a query unless wrapped in a second query?(了解 Oracle 别名 - 为什么除非包含在第二个查询中,否则查询中无法识别别名?)
问题描述
我有一个问题
SELECT COUNT(*) AS "CNT",
imei
FROM devices
执行得很好.我想用 WHERE 语句进一步限制查询.(人为)合乎逻辑的下一步是按以下方式修改查询:
which executes just fine. I want to further restrict the query with a WHERE statement. The (humanly) logical next step is to modify the query followingly:
SELECT COUNT(*) AS "CNT",
imei
FROM devices
WHERE CNT > 1
然而,这会导致错误消息ORA-00904:CNT":标识符无效.出于某种原因,将查询包装在另一个查询中会产生所需的结果:
However, this results in a error message ORA-00904: "CNT": invalid identifier. For some reason, wrapping the query in another query produces the desired result:
SELECT *
FROM (SELECT COUNT(*) AS "CNT",
imei
FROM devices
GROUP BY imei)
WHERE CNT > 1
为什么 Oracle 在第二个查询中无法识别别名CNT"?
Why does Oracle not recognize the alias "CNT" in the second query?
推荐答案
简单的答案是 AS 子句定义了结果中将调用的列,与查询本身.
The simple answer is that the AS clause defines what the column will be called in the result, which is a different scope than the query itself.
在您的示例中,使用 HAVING 子句效果最佳:
In your example, using the HAVING clause would work best:
SELECT COUNT(*) AS "CNT",
imei
FROM devices
GROUP BY imei
HAVING COUNT(*) > 1
这篇关于了解 Oracle 别名 - 为什么除非包含在第二个查询中,否则查询中无法识别别名?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持编程学习网!
本文标题为:了解 Oracle 别名 - 为什么除非包含在第二个查询中,否则查询中无法识别别名?
基础教程推荐
- 如何在 CakePHP 3 中实现 INSERT ON DUPLICATE KEY UPDATE aka upsert? 2021-01-01
- 带有WHERE子句的LAG()函数 2022-01-01
- MySQL根据从其他列分组的值,对两列之间的值进行求和 2022-01-01
- MySQL 5.7参照时间戳生成日期列 2022-01-01
- while 在触发器内循环以遍历 sql 中表的所有列 2022-01-01
- 从字符串 TSQL 中获取数字 2021-01-01
- ORA-01830:日期格式图片在转换整个输入字符串之前结束/选择日期查询的总和 2021-01-01
- CHECKSUM 和 CHECKSUM_AGG:算法是什么? 2021-01-01
- 使用 VBS 和注册表来确定安装了哪个版本和 32 位 2021-01-01
- 带更新的 sqlite CTE 2022-01-01
