在 R 中按组连接列-数据库问题

Concatenating a column by a group in R(在 R 中按组连接列)

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问题描述

假设我有这个员工列表:

Suppose I've got this employee list:

 Dept Date      Name            
----- --------- --------------- 
   30 07-DEC-02 Raphaely        
   30 18-MAY-03 Khoo            
   40 07-JUN-02 Mavris          
   50 01-MAY-03 Kaufling        
   50 14-JUL-03 Ladwig          
   70 07-JUN-02 Baer            
   90 13-JAN-01 De Haan
   90 17-JUN-03 King  
  100 16-AUG-02 Faviet
  100 17-AUG-02 Greenberg 
  110 07-JUN-02 Gietz           
  110 07-JUN-02 Higgins

我想要在 R 中按部门聚合列表(类似于 Oracle PL/SQL 的 LISTAGG 函数) 将生成最后一列:

I want a list aggregation by department in R (similar to Oracle PL/SQL's LISTAGG function) that would product this last column:

 Dept Date      Name            Emp_list
----- --------- --------------- ---------------------------------------------
   30 07-DEC-02 Raphaely        Raphaely; Khoo
   30 18-MAY-03 Khoo            Raphaely; Khoo
   40 07-JUN-02 Mavris          Mavris
   50 01-MAY-03 Kaufling        Kaufling; Ladwig
   50 14-JUL-03 Ladwig          Kaufling; Ladwig
   70 07-JUN-02 Baer            Baer
   90 13-JAN-01 De Haan         De Haan; King
   90 17-JUN-03 King            De Haan; King
  100 16-AUG-02 Faviet          Faviet; Greenberg
  100 17-AUG-02 Greenberg       Faviet; Greenberg
  110 07-JUN-02 Gietz           Gietz; Higgins
  110 07-JUN-02 Higgins         Gietz; Higgins

有什么建议吗?

推荐答案

可以使用ave和paste:

within(mydf, {
  Emp_list <- ave(Name, Dept, FUN = function(x) paste(x, collapse = "; "))
})
#   Dept      Date      Name          Emp_list
# 1    30 07-DEC-02  Raphaely    Raphaely; Khoo
# 2    30 18-MAY-03      Khoo    Raphaely; Khoo
# 3    40 07-JUN-02    Mavris            Mavris
# 4    50 01-MAY-03  Kaufling  Kaufling; Ladwig
# 5    50 14-JUL-03    Ladwig  Kaufling; Ladwig
# 6    70 07-JUN-02      Baer              Baer
# 7    90 13-JAN-01   De Haan     De Haan; King
# 8    90 17-JUN-03      King     De Haan; King
# 9   100 16-AUG-02    Faviet Faviet; Greenberg
# 10  100 17-AUG-02 Greenberg Faviet; Greenberg
# 11  110 07-JUN-02     Gietz    Gietz; Higgins
# 12  110 07-JUN-02   Higgins    Gietz; Higgins

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