sql 2005 中的枢轴

问题描述

我需要旋转一列(数字列).示例需要此数据:

I need to pivot one column (Numbers column). example need this data:

a 1
a 2
b 3
b 4
c 5
d 6
d 7
d 8
d 9
e 10
e 11
e 12
e 13
e 14

看起来像这样

a 1 2
b 3 4
c 5
d 6 7 8 9
e 10 11 12 13 14

任何帮助将不胜感激...

any help would be greatly appreciated...

推荐答案

使用 ROW_NUMBER()、PIVOT 和一些动态 SQL(但不需要游标):

Using ROW_NUMBER(), PIVOT and some dynamic SQL (but no cursor necessary) :

CREATE TABLE [dbo].[stackoverflow_198716](
    [code] [varchar](1) NOT NULL,
    [number] [int] NOT NULL
) ON [PRIMARY]

DECLARE @sql AS varchar(max)
DECLARE @pivot_list AS varchar(max) -- Leave NULL for COALESCE technique
DECLARE @select_list AS varchar(max) -- Leave NULL for COALESCE technique

SELECT @pivot_list = COALESCE(@pivot_list + ', ', '') + '[' + CONVERT(varchar, PIVOT_CODE) + ']'
        ,@select_list = COALESCE(@select_list + ', ', '') + '[' + CONVERT(varchar, PIVOT_CODE) + '] AS [col_' + CONVERT(varchar, PIVOT_CODE) + ']'
FROM (
    SELECT DISTINCT PIVOT_CODE
    FROM (
        SELECT code, number, ROW_NUMBER() OVER (PARTITION BY code ORDER BY number) AS PIVOT_CODE
        FROM stackoverflow_198716
    ) AS rows
) AS PIVOT_CODES

SET @sql = '
;WITH p AS (
    SELECT code, number, ROW_NUMBER() OVER (PARTITION BY code ORDER BY number) AS PIVOT_CODE
    FROM stackoverflow_198716
)
SELECT code, ' + @select_list + '
FROM p
PIVOT (
    MIN(number)
    FOR PIVOT_CODE IN (
        ' + @pivot_list + '
    )
) AS pvt
'

PRINT @sql

EXEC (@sql)

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