• <i id='dHeE1'><tr id='dHeE1'><dt id='dHeE1'><q id='dHeE1'><span id='dHeE1'><b id='dHeE1'><form id='dHeE1'><ins id='dHeE1'></ins><ul id='dHeE1'></ul><sub id='dHeE1'></sub></form><legend id='dHeE1'></legend><bdo id='dHeE1'><pre id='dHeE1'><center id='dHeE1'></center></pre></bdo></b><th id='dHeE1'></th></span></q></dt></tr></i><div id='dHeE1'><tfoot id='dHeE1'></tfoot><dl id='dHeE1'><fieldset id='dHeE1'></fieldset></dl></div>
    <tfoot id='dHeE1'></tfoot>

    <small id='dHeE1'></small><noframes id='dHeE1'>

    <legend id='dHeE1'><style id='dHeE1'><dir id='dHeE1'><q id='dHeE1'></q></dir></style></legend>

      • <bdo id='dHeE1'></bdo><ul id='dHeE1'></ul>

      1. Oracle SQL - 如何检索列的最高 5 个值

        Oracle SQL - How to Retrieve highest 5 values of a column(Oracle SQL - 如何检索列的最高 5 个值)

            <tfoot id='IyHGZ'></tfoot>
            <legend id='IyHGZ'><style id='IyHGZ'><dir id='IyHGZ'><q id='IyHGZ'></q></dir></style></legend>

              <small id='IyHGZ'></small><noframes id='IyHGZ'>

                <tbody id='IyHGZ'></tbody>

                <i id='IyHGZ'><tr id='IyHGZ'><dt id='IyHGZ'><q id='IyHGZ'><span id='IyHGZ'><b id='IyHGZ'><form id='IyHGZ'><ins id='IyHGZ'></ins><ul id='IyHGZ'></ul><sub id='IyHGZ'></sub></form><legend id='IyHGZ'></legend><bdo id='IyHGZ'><pre id='IyHGZ'><center id='IyHGZ'></center></pre></bdo></b><th id='IyHGZ'></th></span></q></dt></tr></i><div id='IyHGZ'><tfoot id='IyHGZ'></tfoot><dl id='IyHGZ'><fieldset id='IyHGZ'></fieldset></dl></div>
                  <bdo id='IyHGZ'></bdo><ul id='IyHGZ'></ul>
                • 本文介绍了Oracle SQL - 如何检索列的最高 5 个值的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着跟版网的小编来一起学习吧!

                  问题描述

                  如何编写一个查询,其中只返回具有最高或最低列值的选定行数.

                  How do you write a query where only a select number of rows are returned with either the highest or lowest column value.

                  即一份薪水最高的 5 名员工的报告?

                  i.e. A report with the 5 highest salaried employees?

                  推荐答案

                  最好的方法是使用解析函数,RANK() 或 DENSE_RANK() ...

                  The best way to do this is with analytic functions, RANK() or DENSE_RANK() ...

                  SQL> select * from (
                    2        select empno
                    3               , sal
                    4               , rank() over (order by sal desc) as rnk
                    5        from emp)
                    6  where rnk <= 5
                    7  /
                  
                       EMPNO        SAL        RNK
                  ---------- ---------- ----------
                        7839       5000          1
                        7788       3000          2
                        7902       3000          2
                        7566       2975          4
                        8083       2850          5
                        7698       2850          5
                  
                  6 rows selected.
                  
                  SQL>
                  

                  DENSE_RANK() 在平局时压缩间隙:

                  DENSE_RANK() compresses the gaps when there is a tie:

                  SQL> select * from (
                    2        select empno
                    3               , sal
                    4               , dense_rank() over (order by sal desc) as rnk
                    5        from emp)
                    6  where rnk <= 5
                    7  /
                  
                       EMPNO        SAL        RNK
                  ---------- ---------- ----------
                        7839       5000          1
                        7788       3000          2
                        7902       3000          2
                        7566       2975          3
                        8083       2850          4
                        7698       2850          4
                        8070       2500          5
                  
                  7 rows selected.
                  
                  SQL>
                  

                  您喜欢哪种行为取决于您的业务需求.

                  Which behaviour you prefer depends upon your business requirements.

                  还有 ROW_NUMBER() 分析函数,我们可以使用它来返回精确的行数.但是,我们应该避免使用基于行号的解决方案,除非业务逻辑乐于在出现平局时任意截断结果集.要求五个最高值按高值排序的前五个记录

                  There is also the ROW_NUMBER() analytic function which we can use to return a precise number of rows. However, we should avoid using solutions based on row number unless the business logic is happy to arbitrarily truncate the result set in the event of a tie. There is a difference between asking for the five highest values and the first five records sorted by high values

                  还有一个使用 ROWNUM 伪列的非解析解.这很笨拙,因为 ROWNUM 在 ORDER BY 子句之前应用,这可能会导致意外结果.很少有理由使用 ROWNUM 而不是 ROW_NUMBER() 或排名函数之一.

                  There is also a non-analytic solution using the ROWNUM pseudo-column. This is clunky because ROWNUM is applied before the ORDER BY clause, which can lead to unexpected results. There is rarely any reason to use ROWNUM instead of ROW_NUMBER() or one of the ranking functions.

                  这篇关于Oracle SQL - 如何检索列的最高 5 个值的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持跟版网!

                  本站部分内容来源互联网,如果有图片或者内容侵犯了您的权益,请联系我们,我们会在确认后第一时间进行删除!

                  相关文档推荐

                  ibtmp1是非压缩的innodb临时表的独立表空间,通过innodb_temp_data_file_path参数指定文件的路径,文件名和大小,默认配置为ibtmp1:12M:autoextend,也就是说在文件系统磁盘足够的情况下,这个文件大小是可以无限增长的。 为了避免ibtmp1文件无止境的暴涨导致
                  SQL query to group by day(按天分组的 SQL 查询)
                  What does SQL clause quot;GROUP BY 1quot; mean?(SQL 子句“GROUP BY 1是什么意思?意思是?)
                  MySQL groupwise MAX() returns unexpected results(MySQL groupwise MAX() 返回意外结果)
                  MySQL SELECT most frequent by group(MySQL SELECT 按组最频繁)
                  Include missing months in Group By query(在 Group By 查询中包含缺失的月份)
                  <i id='eEOKT'><tr id='eEOKT'><dt id='eEOKT'><q id='eEOKT'><span id='eEOKT'><b id='eEOKT'><form id='eEOKT'><ins id='eEOKT'></ins><ul id='eEOKT'></ul><sub id='eEOKT'></sub></form><legend id='eEOKT'></legend><bdo id='eEOKT'><pre id='eEOKT'><center id='eEOKT'></center></pre></bdo></b><th id='eEOKT'></th></span></q></dt></tr></i><div id='eEOKT'><tfoot id='eEOKT'></tfoot><dl id='eEOKT'><fieldset id='eEOKT'></fieldset></dl></div>
                    <legend id='eEOKT'><style id='eEOKT'><dir id='eEOKT'><q id='eEOKT'></q></dir></style></legend>

                  1. <small id='eEOKT'></small><noframes id='eEOKT'>

                        • <tfoot id='eEOKT'></tfoot>

                            <bdo id='eEOKT'></bdo><ul id='eEOKT'></ul>
                              <tbody id='eEOKT'></tbody>