如何选择每组的前N行?

问题描述

我有两个这样的 SQLite 表:

I have two SQLite tables like this:

 AuthorId | AuthorName
----------------------
 1        | Alice
 2        | Bob
 3        | Carol
 ...      | ....


 BookId | AuthorId | Title
----------------------------------
 1      | 1        | aaa1
 2      | 1        | aaa2
 3      | 1        | aaa3
 4      | 2        | ddd1
 5      | 2        | ddd2
 ...    | ...      | ...
 19     | 3        | fff1
 20     | 3        | fff2
 21     | 3        | fff3
 22     | 3        | fff4

我想做一个 SELECT 查询，它将返回每个 AuthorId 的前 N(例如两)行，按标题排序(选择每个作者的前两本书").

I want to make a SELECT query that will return the first N (e.g. two) rows for each AuthorId, ordering by Title ("Select the first two books of each author").

示例输出:

 BookId |  AuthorId | AuthorName | Title
------------------------------------------
 1      |  1        |   Alice    | aaa1
 2      |  1        |   Alice    | aaa1
 4      |  2        |   Bob      | ddd1
 5      |  2        |   Bob      | ddd2
 19     |  3        |   Carol    | fff1
 20     |  3        |   Carol    | fff2

如何构建此查询?

(是的，我找到了一个类似的主题，我知道如何只返回一行(第一行或顶部).问题在于两者).

(Yes, I found a similar topic, and I know how to return only one row (first or top). The problem is with the two).

推荐答案

您可以使用相关子查询进行计数:

You can do the counting using a correlated subquery:

SELECT b.BookId, a.AuthorId, a.AuthorName, b.Title
FROM Author a join
     Book b
     on a.AuthorId = b.AuthorId
where (select count(*)
       from book b2
       where b2.bookId <= b.BookId and b2.AuthorId = b.AuthorId
      ) <= 2;

对于小型数据库，这应该没问题.如果您在 Book(AuthorId, BookId) 上创建复合索引，那么这将有助于查询.

For a small database this should be fine. If you create a composite index on Book(AuthorId, BookId) then that will help the query.

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