Oracle PL/SQL select into 变量

2023-11-02数据库问题
36

本文介绍了Oracle PL/SQL select into 变量的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着跟版网的小编来一起学习吧!

问题描述

我尝试在 SQL Developer 中运行以下查询,但收到错误消息.我试图声明两个局部变量(var_num1 和 payDate),然后设置变量.有谁知道我可能做错了什么?我知道 Oracle SQL 与 SQL Server 略有不同.

I am trying to run the following query in SQL Developer, but I am receiving an error. I am trying to declare two local variables (var_num1 and payDate) and then set the variables. Does anyone know what I can be doing incorrectly? I know Oracle SQL is a little different than SQL Server.

DECLARE
  var_num1 number; 
  payDate date;
 BEGIN 
  var_num1 := 100; 
  payDate := '10/1/2013'
  BEGIN 
    SELECT * FROM Paycode WHERE PaycodeID = var_num1 and PaycodeDate = payDate;
  End;
END; 

<小时>

Error report:
ORA-06550: line 6, column 2:
PLS-00428: an INTO clause is expected in this SELECT statement
06550. 00000 -  "line %s, column %s:
%s"
*Cause:    Usually a PL/SQL compilation error.
*Action:

推荐答案

在 PL/SQL 中不能使用没有 INTO 子句的 SELECT.SELECT 的输出必须存储在某处.例如.表或变量或记录.请参阅下面的示例如何将 SELECT 语句的结果存储到记录中.

You cannot use SELECT without INTO clause in PL/SQL. The output of the SELECT must be stored somewhere. Eg. table or variable or perhaps a record. See example below how to store result of the SELECT statement into record.

DECLARE
  var_num1 number; 
  payDate date;
  v_result Paycode%ROWTYPE;
BEGIN 
  var_num1 := 100; 
  payDate := '10/1/2013';

    SELECT * INTO v_result
    FROM Paycode
    WHERE PaycodeID = var_num1 and PaycodeDate = payDate;

END; 

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