Selecting COUNT(*) with DISTINCT(使用 DISTINCT 选择 COUNT(*))
问题描述
In SQL Server 2005 I have a table cm_production that lists all the code that's been put into production. The table has a ticket_number, program_type, program_name and push_number along with some other columns.
GOAL: Count all the DISTINCT program names by program type and push number.
What I have so far is:
DECLARE @push_number INT;
SET @push_number = [HERE_ADD_NUMBER];
SELECT DISTINCT COUNT(*) AS Count, program_type AS [Type]
FROM cm_production
WHERE push_number=@push_number
GROUP BY program_type
This gets me partway there, but it's counting all the program names, not the distinct ones (which I don't expect it to do in that query). I guess I just can't wrap my head around how to tell it to count only the distinct program names without selecting them. Or something.
Count all the DISTINCT program names by program type and push number
SELECT COUNT(DISTINCT program_name) AS Count,
program_type AS [Type]
FROM cm_production
WHERE push_number=@push_number
GROUP BY program_type
DISTINCT COUNT(*) will return a row for each unique count. What you want is COUNT(DISTINCT <expression>): evaluates expression for each row in a group and returns the number of unique, non-null values.
这篇关于使用 DISTINCT 选择 COUNT(*)的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持编程学习网!
本文标题为:使用 DISTINCT 选择 COUNT(*)
基础教程推荐
- 使用 VBS 和注册表来确定安装了哪个版本和 32 位 2021-01-01
- 如何在 CakePHP 3 中实现 INSERT ON DUPLICATE KEY UPDATE aka upsert? 2021-01-01
- CHECKSUM 和 CHECKSUM_AGG:算法是什么? 2021-01-01
- ORA-01830:日期格式图片在转换整个输入字符串之前结束/选择日期查询的总和 2021-01-01
- 带有WHERE子句的LAG()函数 2022-01-01
- MySQL 5.7参照时间戳生成日期列 2022-01-01
- 从字符串 TSQL 中获取数字 2021-01-01
- 带更新的 sqlite CTE 2022-01-01
- MySQL根据从其他列分组的值,对两列之间的值进行求和 2022-01-01
- while 在触发器内循环以遍历 sql 中表的所有列 2022-01-01
