int 类型的字面量 xyz 超出范围

The literal xyz of type int is out of range(int 类型的字面量 xyz 超出范围)

问题描述

我目前正在使用 Java 中的数据类型，如果我理解正确，类型 long 接受介于 -9,223,372,036,854,775,808 到 +9,223,372,036,854,775,807 之间的值.现在正如您在下面看到的，我创建了一个名为 testLong 的 long 变量，尽管当我插入 9223372036854775807 作为值时，我收到一条错误消息:

I am working with data types at the moment in Java, and if I have understood correctly the type long accepts a value between the ranges of -9,223,372,036,854,775,808 to +9,223,372,036,854,775,807. Now as you can see below, I have create a long variable called testLong, although when I insert 9223372036854775807 as the value, I get an error stating:

int 类型的字面量 9223372036854775807 超出范围.

The literal 9223372036854775807 of the type int is out of range.

我不知道为什么它把 long 数据类型称为 int.

I don't know why it is referring to the long data type as an int.

有人有什么想法吗?

代码:

char testChar = 01;
byte testByte = -128;
int testInt = -2147483648;
short testShort = -32768;
long testLong = 9223372036854775807;
float testFoat;
double testDouble = 4.940656458412;
boolean testBool = true;

推荐答案

在末尾加一个大写的L:

long value = 9223372036854775807L;

否则，编译器将尝试将文字解析为 int，因此会出现错误消息

Otherwise, the compiler will try to parse the literal as an int, hence the error message

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