本文介绍了将 key=value 的字符串解析为 Map的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着跟版网的小编来一起学习吧！
问题描述
我正在使用一个提供 XML 的 API，我需要从一个实际上是字符串的标签中获取地图.示例:
I'm using an API that gives me a XML and I need to get a map from one tag which is actually a string. Example:
拥有
Billable=7200,Overtime=false,TransportCosts=20$
我需要
["Billable"="7200","Overtime=false","TransportCosts"="20$"]
问题是字符串是完全动态的，所以，它可以像
The problem is that the string is totally dynamic, so, it can be like
Overtime=true,TransportCosts=one, two, three
Overtime=true,TransportCosts=1= 1,two, three,Billable=7200
所以我不能只用逗号分隔，然后用等号分隔.是否可以使用正则表达式将类似的字符串转换为地图?
So I can not just split by comma and then by equal sign. Is it possible to convert a string like those to a map using a regex?
到目前为止我的代码是:
My code so far is:
private Map<String, String> getAttributes(String attributes) {
final Map<String, String> attr = new HashMap<>();
if (attributes.contains(",")) {
final String[] pairs = attributes.split(",");
for (String s : pairs) {
if (s.contains("=")) {
final String pair = s;
final String[] keyValue = pair.split("=");
attr.put(keyValue[0], keyValue[1]);
}
}
return attr;
}
return attr;
}
提前致谢
推荐答案
你可以用
(w+)=(.*?)(?=,w+=|$)
请参阅 正则表达式演示.
详情
(w+)- 第 1 组:一个或多个单词字符=- 一个等号(.*?)- 第 2 组:除换行符以外的任何零个或多个字符，尽可能少(?=,w+=|$)- 需要,，然后是 1+ 个单词字符，然后是=，或字符串的结尾紧挨当前位置的右侧.
(w+)- Group 1: one or more word chars=- an equal sign(.*?)- Group 2: any zero or more chars other than line break chars, as few as possible(?=,w+=|$)- a positive lookahead that requires a,, then 1+ word chars, and then=, or end of string immediately to the right of the current location.
Java 代码:
public static Map<String, String> getAttributes(String attributes) {
Map<String, String> attr = new HashMap<>();
Matcher m = Pattern.compile("(\w+)=(.*?)(?=,\w+=|$)").matcher(attributes);
while (m.find()) {
attr.put(m.group(1), m.group(2));
}
return attr;
}
Java 测试:
String s = "Overtime=true,TransportCosts=1= 1,two, three,Billable=7200";
Map<String,String> map = getAttributes(s);
for (Map.Entry entry : map.entrySet()) {
System.out.println(entry.getKey() + "=" + entry.getValue());
}
结果:
Overtime=true
Billable=7200
TransportCosts=1= 1,two, three
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