本文介绍了HashMap<int[],string>通过考虑它们的值来映射整数数组的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着跟版网的小编来一起学习吧!
问题描述
Given the following code, I get a null (what I want is "1234"). But I wish to have a map that could consider the key as equals, if the contents of int[] are equals (rather than consider that the references of int[]), how should I do it?
HashMap<int[], String> maps=new HashMap<int[], String>();
int[] i=new int[]{1,2,3};
int[] j=new int[]{1,2,3};
maps.put(i,"1234");
System.out.print(maps.get(j));
I am opened to any map that allows keeping int[] as the key (including TreeMap) and so on, with the side condition that if that does not hamper on the effectiveness of the map accessing time.
解决方案
No way to do that with arrays, because they don't override equals() and hashCode(). You should define your own class wrapping the array, which would override equals() and hashCode() or use a List<Integer> as key instead.
这篇关于HashMap<int[],string>通过考虑它们的值来映射整数数组的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持跟版网!
The End


大气响应式网络建站服务公司织梦模板
高端大气html5设计公司网站源码
织梦dede网页模板下载素材销售下载站平台(带会员中心带筛选)
财税代理公司注册代理记账网站织梦模板(带手机端)
成人高考自考在职研究生教育机构网站源码(带手机端)
高端HTML5响应式企业集团通用类网站织梦模板(自适应手机端)