问题描述

对不起，如果标题具有误导性或令人困惑，但这是我的困境.我正在输入一个字符串，并想为字母表中的每个大写字母(A=1，.. Z=26)分配一个值，然后添加该字符串中每个字母的值.

Sorry if the title is misleading or is confusing, but here is my dilemma. I am inputting a string, and want to assign a value to each capitalized letter in the alphabet (A=1, .. Z=26) and then add the values of each letter in that string.

示例: ABCD = 10(因为 1 + 2 + 3 + 4)

Example: ABCD = 10 (since 1 + 2 + 3 + 4)

但我不知道如何将字符串中的所有值相加

But I don't know how to add all the values in the string

注意:这仅适用于大写字母和字符串

NOTE: This is only for capitalized letters and strings

public class Test {

    public static void main(String[] args) {

        Scanner scannerTest = new Scanner(System.in);
        System.out.println("Enter a name here: ");

        String str = scannerTest.nextLine();

        char[] ch = str.toCharArray();
        int temp_integer = 64;

        for (char c : ch) {
            int temp = (int) c;

               if (temp <= 90 & temp >= 65){
            int sum = (temp - temp_integer);
            System.out.println(sum);
        }   
      }
    }
}

所以，如您所见，我打印出每次循环的总和，含义:如果我输入AB"，输出将是1和2.

So, as you can see I print out the sum for each time its looped, meaning: if I input "AB", the output will be 1 and 2.

但是，我想更进一步，将这两个值加在一起，但我很困惑，有什么建议或帮助吗?(注意:这不是作业或任何东西，只是练习问题集)

However, I want to go a step further, and add these two values together, but I'm stumped, any suggestions or help? (NOTE: this is not a assignment or anything, just practising problem sets)

推荐答案

我更喜欢使用字符文字.你知道范围是A到Z(1到26)，所以你可以减去'A'从每个 char 开始(但您需要添加 1，因为它不是从 0 开始的).我还会在输入行上调用 toUpperCase .类似的，

I would prefer to use the character literals. You know that the range is A to Z (1 to 26), so you can subtract 'A' from each char (but you need to add 1 because it doesn't start at 0). I would also call toUpperCase on the input line. Something like,

Scanner scannerTest = new Scanner(System.in);
System.out.println("Enter a name here: ");
String str = scannerTest.nextLine().toUpperCase();
int sum = 0;
for (char ch : str.toCharArray()) {
    if (ch >= 'A' && ch <= 'Z') {
        sum += 1 + ch - 'A';
    }
}
System.out.printf("The sum of %s is %d%n", str, sum);

我用你的例子测试过

Enter a name here: 
ABCD
The sum of ABCD is 10

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