Java,使用迭代器搜索 ArrayList 并删除匹配的对象

Java, Using Iterator to search an ArrayList and delete matching objects(Java,使用迭代器搜索 ArrayList 并删除匹配的对象)
本文介绍了Java,使用迭代器搜索 ArrayList 并删除匹配的对象的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着跟版网的小编来一起学习吧!

问题描述

基本上,用户提交一个字符串,迭代器在 ArrayList 中搜索该字符串.找到后,迭代器将删除包含该字符串的对象.

Basically, the user submits a String which the Iterator searches an ArrayList for. When found the Iterator will delete the object containing the String.

因为这些对象中的每一个都包含两个字符串,所以我很难将这些行写成一个.

Because each of these objects contain two Strings, I am finding trouble writing these lines as one.

Friend current = it.next();
String currently = current.getFriendCaption();

感谢您的帮助!

推荐答案

你不需要它们在一行,只要在匹配时使用 remove 删除一个项目:

You don't need them on one line, just use remove to remove an item when it matches:

Iterator<Friend> it = list.iterator();
while (it.hasNext()) {
    if (it.next().getFriendCaption().equals(targetCaption)) {
        it.remove();
        // If you know it's unique, you could `break;` here
    }
}

完整演示:

import java.util.*;

public class ListExample {
    public static final void main(String[] args) {
        List<Friend>    list = new ArrayList<Friend>(5);
        String          targetCaption = "match";

        list.add(new Friend("match"));
        list.add(new Friend("non-match"));
        list.add(new Friend("match"));
        list.add(new Friend("non-match"));
        list.add(new Friend("match"));

        System.out.println("Before:");
        for (Friend f : list) {
            System.out.println(f.getFriendCaption());
        }

        Iterator<Friend> it = list.iterator();
        while (it.hasNext()) {
            if (it.next().getFriendCaption().equals(targetCaption)) {
                it.remove();
                // If you know it's unique, you could `break;` here
            }
        }

        System.out.println();
        System.out.println("After:");
        for (Friend f : list) {
            System.out.println(f.getFriendCaption());
        }

        System.exit(0);
    }

    private static class Friend {
        private String friendCaption;

        public Friend(String fc) {
            this.friendCaption = fc;
        }

        public String getFriendCaption() {
            return this.friendCaption;
        }

    }
}

输出:

$ java ListExample 
Before:
match
non-match
match
non-match
match

After:
non-match
non-match

这篇关于Java,使用迭代器搜索 ArrayList 并删除匹配的对象的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持跟版网!

本站部分内容来源互联网,如果有图片或者内容侵犯了您的权益,请联系我们,我们会在确认后第一时间进行删除!

相关文档推荐

How to send data to COM PORT using JAVA?(如何使用 JAVA 向 COM PORT 发送数据?)
How to make a report page direction to change to quot;rtlquot;?(如何使报表页面方向更改为“rtl?)
Use cyrillic .properties file in eclipse project(在 Eclipse 项目中使用西里尔文 .properties 文件)
Is there any way to detect an RTL language in Java?(有没有办法在 Java 中检测 RTL 语言?)
How to load resource bundle messages from DB in Java?(如何在 Java 中从 DB 加载资源包消息?)
How do I change the default locale settings in Java to make them consistent?(如何更改 Java 中的默认语言环境设置以使其保持一致?)