问题描述
我有一些以秒为单位的时间戳(即 Unix 时间戳)的 JSON:
I've got some JSON that has timestamps in seconds (i.e. a Unix timestamp):
{"foo":"bar","timestamp":1386280997}
要求 Jackson 将其反序列化为具有 DateTime 字段的对象以获取时间戳,结果为 1970-01-17T01:11:25.983Z,这是纪元之后不久的时间,因为 Jackson 假设它毫秒.除了撕开 JSON 并添加一些零之外,我如何让 Jackson 理解 seconds 时间戳?
Asking Jackson to deserialize this into an object with a DateTime field for the timestamp results in 1970-01-17T01:11:25.983Z, a time shortly after the epoch because Jackson is assuming it to be in milliseconds. Aside from ripping apart the JSON and adding some zeros, how might I get Jackson to understand the seconds timestamp?
推荐答案
我写了一个自定义deserializer 以秒为单位处理时间戳(Groovy 语法).
I wrote a custom deserializer to handle timestamps in seconds (Groovy syntax).
class UnixTimestampDeserializer extends JsonDeserializer<DateTime> {
Logger logger = LoggerFactory.getLogger(UnixTimestampDeserializer.class)
@Override
DateTime deserialize(JsonParser jp, DeserializationContext ctxt) throws IOException, JsonProcessingException {
String timestamp = jp.getText().trim()
try {
return new DateTime(Long.valueOf(timestamp + '000'))
} catch (NumberFormatException e) {
logger.warn('Unable to deserialize timestamp: ' + timestamp, e)
return null
}
}
}
然后我注释了我的 POGO 以将其用作时间戳:
And then I annotated my POGO to use that for the timestamp:
class TimestampThing {
@JsonDeserialize(using = UnixTimestampDeserializer.class)
DateTime timestamp
@JsonCreator
public TimestampThing(@JsonProperty('timestamp') DateTime timestamp) {
this.timestamp = timestamp
}
}
这篇关于我如何反序列化以杰克逊为单位的时间戳?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持跟版网!


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