问题描述

我有一些以秒为单位的时间戳(即 Unix 时间戳)的 JSON:

I've got some JSON that has timestamps in seconds (i.e. a Unix timestamp):

{"foo":"bar","timestamp":1386280997}

要求 Jackson 将其反序列化为具有 DateTime 字段的对象以获取时间戳，结果为 1970-01-17T01:11:25.983Z，这是纪元之后不久的时间，因为 Jackson 假设它毫秒.除了撕开 JSON 并添加一些零之外，我如何让 Jackson 理解 seconds 时间戳?

Asking Jackson to deserialize this into an object with a DateTime field for the timestamp results in 1970-01-17T01:11:25.983Z, a time shortly after the epoch because Jackson is assuming it to be in milliseconds. Aside from ripping apart the JSON and adding some zeros, how might I get Jackson to understand the seconds timestamp?

推荐答案

我写了一个自定义deserializer 以秒为单位处理时间戳(Groovy 语法).

I wrote a custom deserializer to handle timestamps in seconds (Groovy syntax).

class UnixTimestampDeserializer extends JsonDeserializer<DateTime> {
    Logger logger = LoggerFactory.getLogger(UnixTimestampDeserializer.class)

    @Override
    DateTime deserialize(JsonParser jp, DeserializationContext ctxt) throws IOException, JsonProcessingException {
        String timestamp = jp.getText().trim()

        try {
            return new DateTime(Long.valueOf(timestamp + '000'))
        } catch (NumberFormatException e) {
            logger.warn('Unable to deserialize timestamp: ' + timestamp, e)
            return null
        }
    }
}

然后我注释了我的 POGO 以将其用作时间戳:

And then I annotated my POGO to use that for the timestamp:

class TimestampThing {
    @JsonDeserialize(using = UnixTimestampDeserializer.class)
    DateTime timestamp

    @JsonCreator
    public TimestampThing(@JsonProperty('timestamp') DateTime timestamp) {
        this.timestamp = timestamp
    }
}

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