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      在java中将两个整数除以一个double

      Dividing two integers to a double in java(在java中将两个整数除以一个double)
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              1. 本文介绍了在java中将两个整数除以一个double的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着跟版网的小编来一起学习吧!

                问题描述

                我可以看到这是新程序员的常见问题,但是我没有成功地为我的代码实现任何解决方案.基本上我想将 w 和 v 相除,它们必须保存到一个双变量中.但它打印 [0.0, 0.0, ... , 0.0]

                I can see this is a common problem for new programmers, however I didn't succeed in implementing any of the solution to my code. Basically I want to divide w and v, which must be saved to a double variable. But it prints [0.0, 0.0, ... , 0.0]

                public static double density(int[] w, int[] v){
                double d = 0;
                    for(L = 0; L < w.length; L++){
                        d = w[L]  /v[L];
                    }
                    return d;
                }
                

                推荐答案

                这里的这一行 d = w[L]/v[L]; 发生在几个步骤中

                This line here d = w[L] /v[L]; takes place over several steps

                d = (int)w[L]  / (int)v[L]
                d=(int)(w[L]/v[L])            //the integer result is calculated
                d=(double)(int)(w[L]/v[L])    //the integer result is cast to double
                

                换句话说,在你转换成双精度之前,精度已经消失了,你需要先转换成双精度,所以

                In other words the precision is already gone before you cast to double, you need to cast to double first, so

                d = ((double)w[L])  / (int)v[L];
                

                这会强制 java 在整个过程中使用双精度数学,而不是使用整数数学,然后在最后强制转换为双精度

                This forces java to use double maths the whole way through rather than use integer maths and then cast to double at the end

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