本文介绍了如何制作“打开方式"对话框?的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着跟版网的小编来一起学习吧！
问题描述
I made a program to search for .txt files.
If I click a file it means that the "open with" dialog box should appear, and that dialog box will contain a list of all installed programs.
I am using this code for searching through the files:
public File[] finder( String dirName)
{
// Create a file object on the directory.
File dir = new File(dirName);
// Return a list of all files in the directory.
return dir.listFiles(new FilenameFilter();
}
public boolean accept(File dir, String filename)
{
return filename.endsWith(".txt");
}
What Java code can I use to make the "open with" dialog box appear?
解决方案
You should use FileChooser for this. Take a look here:
//Create a file chooser
final JFileChooser fc = new JFileChooser();
...
//In response to a button click:
int returnVal = fc.showOpenDialog(aComponent);
public void actionPerformed(ActionEvent e) {
//Handle open button action.
if (e.getSource() == openButton) {
int returnVal = fc.showOpenDialog(FileChooserDemo.this);
if (returnVal == JFileChooser.APPROVE_OPTION) {
File file = fc.getSelectedFile();
//This is where a real application would open the file.
log.append("Opening: " + file.getName() + "." + newline);
} else {
log.append("Open command cancelled by user." + newline);
}
} ...
}
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