Swagger 无法为 HTTP“PATCH"生成文档.

Swagger Is not able to produce documentation for HTTP quot;PATCHquot;(Swagger 无法为 HTTP“PATCH生成文档.)

问题描述

我已遵循以下
博客条目:http://kingsfleet.blogspot.co.uk/2014/02/transparent-patch-support-in-jax-rs-20.html
https://github.com/jersey/jersey/tree/2.6/examples/http-patch
在 Jersey 2.6 中创建支持 HTTPPATCH"方法的端点依赖版本:

I Have followed the below
blog entry: http://kingsfleet.blogspot.co.uk/2014/02/transparent-patch-support-in-jax-rs-20.html
https://github.com/jersey/jersey/tree/2.6/examples/http-patch
To create end point to support HTTP "PATCH" method in Jersey 2.6 Dependency Versions:

-Jersey: 2.6
-swagger-jersey2-jaxrs_2.10: 1.3.12

问题?为什么 Patch 端点没有被列为 swagger ui 文档的一部分?

Question? Why Patch end point is not getting listed as part of the swagger ui documentation?

分析:

如果我使用此注释进行注释，则会生成该端点的文档，但没有交互.

If I am annotating with this annotation, then documentation for that end point getting generated, but no interaction .

@com.wordnik.swagger.jaxrs.PATCH

配置

JerssyApplicationInitializer

packages(true, "com.test.account.endpoint", "com.wordnik.swagger.jaxrs.json");
        //Swagger Configuration
        register(new ApiListingResourceJSON(), 10);
        register(JerseyApiDeclarationProvider.class);
        register(JerseyResourceListingProvider.class);

        //Genson Converter
        register(GensonJsonConverter.class, 1);
        register(createMoxyJsonResolver());

我不确定，如果我遗漏了什么，任何帮助或指南都会有所帮助.

I am not sure, if I am missing something, any help or guide will be helpful.

补丁方法文档:

 public static final String PATCH_MEDIA_TYPE = "application/json-patch+json";
    @PATCH
        //@com.wordnik.swagger.jaxrs.PATCH
        @PreAuthorize(userAuthenticationRequire=true)
        @Consumes(PATCH_MEDIA_TYPE)
        @Path("{id: .\d+}")
        @ApiOperation(value = "Update Client Details in UIM System."
                    , response = State.class
                    , notes="Requesting User, should be the owner of the Client."
                    , consumes = PATCH_MEDIA_TYPE)
        @ApiResponses({
            @ApiResponse(code = _401, message = "If the access token is invalid.", response = String.class),
            @ApiResponse(code = _498, message = "If the access token is expired.", response = String.class),
            @ApiResponse(code = _420, message = "If Provided Input is not valid according to requirment specification."),
            @ApiResponse(code = _404, message = "If no client/app Found."),
            @ApiResponse(code = _200, message = "If Client Account has been Updated successfully. ", response=String.class)
        })
        public State updateClientDetails(@ApiParam(value="Client Id to be Updated.", required=true) @PathParam(CLIENT_ID) String clientId
                , @ApiParam(value = "Updated field and Value.", required = true) final State newState){
            //LOG.info("[ENTRY]- Received requst for updating Client {} from System.", clientId);
            System.out.println("----->" + someBean.test());
            //LOG.info("[EXIT]- Client Id {} Updation has been completed.", clientId);
            Test t = new Test();
            t.name = "Hello Test";
            System.out.println(t.name);
            return newState;
        }

推荐答案

看看你的 index.html.控制哪些 HTTP 操作是交互式的——通过将其更改为:

Take a look at your index.html. That controls which HTTP operations are interactive--by changing it to this:

  window.swaggerUi = new SwaggerUi({
    url: url,
    dom_id: "swagger-ui-container",
    supportedSubmitMethods: ['get', 'post', 'put', 'delete', 'patch'],

您将在 PATCH 方法上进行交互:

You will have interaction on the PATCH method:

这篇关于Swagger 无法为 HTTP“PATCH"生成文档.的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持编程学习网！