问题描述
如何在运行时获取当前运行的JVM的可执行文件的位置?我想使用 ProcessBuilder 类将另一个 JVM 实例化为子进程.
How does one obtain the location of the executable of the currently running JVM during runtime? I would like to instantiate another JVM as a subprocess using the ProcessBuilder class.
我知道有 java.home 系统属性，但这并没有指定 JVM 可执行文件的位置.我知道我可以做这样的事情来获得路径:
I am aware that there is the java.home System property, but this doesn't specify the location of the JVM executable. I understand I could do something like this to get the path:
System.getProperties().getProperty("java.home") + File.pathSeparator + "bin" + File.pathSeparator + "java"
此代码与平台无关，因为 Windows 可执行文件的名称是 java.exe，而不是 java.有没有办法获取考虑平台特性的 JVM 可执行文件的路径?
This code isn't platform independent, because the Windows executable's name is java.exe, not java. Is there a way to get the path of the JVM executable that takes the platform's idiosyncrasies into account?
推荐答案
您总是可以只使用 os.name 来检查用户是否在运行 Windows.这将在
You could always just use os.name to check if the user is running Windows or not. That'll work on OS X, Linux and Windows at
String jvm_location;
if (System.getProperty("os.name").startsWith("Win")) {
jvm_location = System.getProperties().getProperty("java.home") + File.separator + "bin" + File.separator + "java.exe";
} else {
jvm_location = System.getProperties().getProperty("java.home") + File.separator + "bin" + File.separator + "java";
}
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