如何在 Android 中设置字符串解析的时区

2023-09-25Java开发问题

本文介绍了如何在 Android 中设置字符串解析的时区的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着跟版网的小编来一起学习吧！

问题描述

我尝试解析一个字符串并设置一个时区，但我无法产生想要的结果.

I try to parse a String and set a time zone, but I can't produce the desired result.

String dtc = "2014-04-02T07:59:02.111Z";
SimpleDateFormat readDate = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSS'Z'");
Date date = null;
try {
   date = readDate.parse(dtc);
   Log.d("myLog", "date "+date);
} catch (ParseException e) {
   Log.d("myLog", "dateExcep " + e);
}

SimpleDateFormat writeDate = new SimpleDateFormat("dd.MM.yyyy, HH.mm"); 
writeDate.setTimeZone(TimeZone.getTimeZone("GMT+04:00"));
String dateString = writeDate.format(date);

在变量dateString"的输出仍然给出时间 07:59:02 ，我想提前 +4 小时，即 11:59:02

At the output of the variable "dateString" still gives the time 07:59:02 , and I want to make it +4 hours in advance that is 11:59:02

推荐答案

您需要指示读取格式化程序将输入解释为 UTC(GMT - 请记住 Z 代表 ISO-8601 格式的 UTC):

You need to instruct the read-formatter to interprete the input as UTC (GMT - remember that Z stands for UTC in ISO-8601-format):

String dtc = "2014-04-02T07:59:02.111Z";
SimpleDateFormat readDate = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSS'Z'");
readDate.setTimeZone(TimeZone.getTimeZone("GMT")); // missing line
Date date = readDate.parse(dtc);
SimpleDateFormat writeDate = new SimpleDateFormat("dd.MM.yyyy, HH.mm");
writeDate.setTimeZone(TimeZone.getTimeZone("GMT+04:00"));
String s = writeDate.format(date);

然后你会得到:

02.04.2014, 11.59

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