“未找到匹配项"使用 matcher 的 group 方法时

问题描述

我正在使用 Pattern/Matcher 来获取 HTTP 响应中的响应代码.groupCount 返回 1，但尝试获取时出现异常！知道为什么吗?

I'm using Pattern/Matcher to get the response code in an HTTP response. groupCount returns 1, but I get an exception when trying to get it! Any idea why?

代码如下:

//get response code
String firstHeader = reader.readLine();
Pattern responseCodePattern = Pattern.compile("^HTTP/1\.1 (\d+) OK$");
System.out.println(firstHeader);
System.out.println(responseCodePattern.matcher(firstHeader).matches());
System.out.println(responseCodePattern.matcher(firstHeader).groupCount());
System.out.println(responseCodePattern.matcher(firstHeader).group(0));
System.out.println(responseCodePattern.matcher(firstHeader).group(1));
responseCode = Integer.parseInt(responseCodePattern.matcher(firstHeader).group(1));

这是输出:

HTTP/1.1 200 OK
true
1
Exception in thread "Thread-0" java.lang.IllegalStateException: No match found
 at java.util.regex.Matcher.group(Unknown Source)
 at cs236369.proxy.Response.<init>(Response.java:27)
 at cs236369.proxy.ProxyServer.start(ProxyServer.java:71)
 at tests.Hw3Tests$1.run(Hw3Tests.java:29)
 at java.lang.Thread.run(Unknown Source)

推荐答案

pattern.matcher(input) 总是创建一个新的匹配器，所以你需要调用 matches() 再次.

pattern.matcher(input) always creates a new matcher, so you'd need to call matches() again.

试试:

Matcher m = responseCodePattern.matcher(firstHeader);
m.matches();
m.groupCount();
m.group(0); //must call matches() first
...

这篇关于“未找到匹配项"使用 matcher 的 group 方法时的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持跟版网！