在这种情况下，可以“a != a"；返回“真"?

问题描述

java.lang.Math#min(double, double):

public static double min(double a, double b) {
    if (a != a) return a; // a is NaN
    if (a == 0.0d && b == 0.0d && Double.doubleToLongBits(b) == negativeZeroDoubleBits) return b;
    return (a <= b) ? a : b;
}

在什么情况下 a != a 会返回 true?似乎是当 a 为 NaN 时，但我无法想象一个例子.可以提供一份吗?

In which case could a != a return true? It seems that it's when a is NaN, but I can't imagine an example. Could you please provide one?

推荐答案

一个简单的例子是

double d = Double.NaN; // or
double d = 0.0/0.0; // or
double d = Double.POSITIVE_INFINITY + Double.NEGATIVE_INFINITY;
if (Double.isNaN(a)) { // tests if a != a
   // do something

BTW Double.compare() 确实认为 NaN 相等

BTW Double.compare() does see NaN as equal

if (Double.compare(d, d) == 0) // always.

对于任何类型和值，多线程都是可能的.例如

With multiple threads this is possible for any type and value. e.g.

if (a != /* another thread changes 'a' */ a) {
    // a thread changed a while you were looking at it.

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