弹簧规范和可分页

问题描述

Specification和Pageable如何一起使用?

personelRepository.java

@Query("SELECT e FROM PersonelEntity e ")
List<PersonelEntity> findData(Specification<PersonelEntity>  test, Pageable pageable);

personelService.java

public List<PersonelEntity> filteredData(Specification<PersonelEntity> filter,Pageable  pageable){
    List<PersonelEntity> filteredData = personelRepository.findData(filter,pageable);
    return filteredData;
}

personelController.java

Pageable reqCount = new PageRequest(0, 10);
Specification<PersonelEntity> filter = new FilterSpecification<PersonelEntity>(new SearchCriteria("name", "=","lux"));
personels = personelService.findData(filter,reqCount);

当我运行它时，我会收到这样的错误.但是，如果我像 findAll(Pageable page) 和 findAll(Specification filter) 那样分别调用 findAll() 函数，它就可以工作.但是不能一起用.

When I run it I get an error like this. But if I call findAll() function separately like findAll(Pageable page) and findAll(Specification filter) it works. But I can not use it together.

java.lang.IllegalArgumentException: Parameter with that position [1] did not exist
    at org.hibernate.jpa.spi.BaseQueryImpl.findParameterRegistration(BaseQueryImpl.java:502) ~[hibernate-entitymanager-5.0.12.Final.jar:5.0.12.Final]
    at org.hibernate.jpa.spi.BaseQueryImpl.setParameter(BaseQueryImpl.java:692) ~[hibernate-entitymanager-5.0.12.Final.jar:5.0.12.Final]
    at org.hibernate.jpa.spi.AbstractQueryImpl.setParameter(AbstractQueryImpl.java:181) ~[hibernate-entitymanager-5.0.12.Final.jar:5.0.12.Final]
    at org.hibernate.jpa.spi.AbstractQueryImpl.setParameter(AbstractQueryImpl.java:32) ~[hibernate-entitymanager-5.0.12.Final.jar:5.0.12.Final]
    at org.springframework.data.jpa.repository.query.ParameterBinder.bind(ParameterBinder.java:141) ~[spring-data-jpa-1.11.1.RELEASE.jar:na]
    at org.springframework.data.jpa.repository.query.StringQueryParameterBinder.bind(StringQueryParameterBinder.java:61) ~[spring-data-jpa-1.11.1.RELEASE.jar:na]
    at org.springframework.data.jpa.repository.query.ParameterBinder.bind(ParameterBinder.java:101) ~[spring-data-jpa-1.11.1.RELEASE.jar:na]
    at org.springframework.data.jpa.repository.query.SpelExpressionStringQueryParameterBinder.bind(SpelExpressionStringQueryParameterBinder.java:69) ~[spring-data-jpa-1.11.1.RELEASE.jar:na]
    at org.springframework.data.jpa.repository.query.ParameterBinder.bindAndPrepare(ParameterBinder.java:161) ~[spring-data-jpa-1.11.1.RELEASE.jar:na]
    at org.springframework.data.jpa.repository.query.ParameterBinder.bindAndPrepare(ParameterBinder.java:152) ~[spring-data-jpa-1.11.1.RELEASE.jar:na]
    at org.springframework.data.jpa.repository.query.AbstractStringBasedJpaQuery.doCreateQuery(AbstractStringBasedJpaQuery.java:81) ~[spring-data-jpa-1.11.1.RELEASE.jar:na]
    at org.springframework.data.jpa.repository.query.AbstractJpaQuery.createQuery(AbstractJpaQuery.java:190) ~[spring-data-jpa-1.11.1.RELEASE.jar:na]
    at org.springframework.data.jpa.repository.query.JpaQueryExecution$CollectionExecution.doExecute(JpaQueryExecution.java:121) ~[spring-data-jpa-1.11.1.RELEASE.jar:na]
    at org.springframework.data.jpa.repository.query.JpaQueryExecution.execute(JpaQueryExecution.java:85) ~[spring-data-jpa-1.11.1.RELEASE.jar:na]

推荐答案

编辑personelService.java，删除personelRepository上的findData函数解决.我使用 springframework.data.jpa.repository.JpaRepository findAll() 函数并且它有效.

Solve by editing personelService.java and delete findData function on personelRepository. I use springframework.data.jpa.repository.JpaRepository findAll() function and it works.

public List<PersonelEntity> filteredData (Specification<PersonelEntity> spec, Pageable pageable){
    Page<PersonelEntity> pageData = personelRepository.findAll(spec,pageable);
    List<PersonelEntity> filteredData = pageData.getContent();
    return filteredData;
}

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