'设置<NSObject>'没有名为“anyObject"的成员.

问题描述

我正在检查是否选择了一个元素.

I'm checking to see if an element has been selected.

func touchesBegan(touches: Set<NSObject>, withEvent event: UIEvent)
{
    // First, see if the game is in a paused state
    if !gamePaused
    {
        // Declare the touched symbol and its location on the screen
        let touch = touches.anyObject! as? UITouch
        let location = touch.locationInNode(symbolsLayer)

这之前在 Xcode 6.2 中编译得很好，但随着 6.3 的更新，let touch = touches.anyObject！as?UITouch"这行会抛出错误:

And this had previously compiled fine in Xcode 6.2 but with a 6.3 update, the line "let touch = touches.anyObject! as? UITouch" is throwing the error:

Set"没有名为anyObject"的成员

'Set' does not have a member named 'anyObject'

我已经阅读了许多类似的问题，但我似乎无法理解要使用该值，您需要先解包"它.尤其是因为答案似乎集中在通知上.

I've read through many similar question, but I can't seem to wrap my head around "To use the value, you need to "unwrap" it first." Especially because the answers seem to focus on notifications.

非常感谢.W

推荐答案

let touch =  touches.first as? UITouch

.first 可以让你访问 UITouch 的第一个对象.

.first can allow you to access first object of UITouch.

由于 Xcode 6.3 使用 Swift (1.2) 的更新版本，您需要将旧代码转换为 Swift 1.2(编辑 -> 转换 -> 到最新的 Swift).

Since Xcode 6.3 uses an updated version of Swift (1.2) you need to convert your old code into Swift 1.2 (Edit -> convert -> To lastest Swift).

Swift 1.2，使用 Set's(Swift 中的新功能)而不是使用 NSSet's(Objective-C 中的旧功能).因此，touchbegan 函数也将其参数从 NSSet 更改为 Set.

Swift 1.2, uses Set’s (new in Swift) instead of using NSSet’s (old one in Objective-C). Thus the touchbegan function also changes its parameters from NSSet to Set.

欲了解更多信息，参考这个

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