如何以编程方式将触摸事件伪造为 UIButton?

问题描述

我正在编写一些单元测试，并且由于这个特定应用程序的性质，重要的是我要在 UI 链中尽可能高.所以，我想做的是以编程方式触发按钮按下，就好像用户按下了 GUI 中的按钮一样.

I'm writing some unit tests and, because of the nature of this particular app, it's important that I get as high up the UI chain as possible. So, what I'd like to do is programmatically trigger a button-press, as if the user had pressed the button in the GUI.

(是的，是的——我可以只调用 IBAction 选择器，但同样，这个特定应用程序的性质使得我假装实际按下按钮很重要，以便从按钮本身调用 IBAction.)

(Yes, yes -- I could just call the IBAction selector but, again, the nature of this particular app makes it important that I fake the actual button press, such that the IBAction be called from the button, itself.)

这样做的首选方法是什么?

What's the preferred method of doing this?

推荐答案

原来如此

[buttonObj sendActionsForControlEvents:UIControlEventTouchUpInside];

在这种情况下，我得到了我需要的东西.

got me exactly what I needed, in this case.

不要忘记在主线程中执行此操作，以获得类似于用户按下的结果.

Don't forget to do this in the main thread, to get results similar to a user-press.

对于 Swift 3:

buttonObj.sendActions(for: .touchUpInside)

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