Swift - 将版本数组排序为字符串

Swift - Sort array of versions as strings(Swift - 将版本数组排序为字符串)

问题描述

我有一个随机排列的字符串数组(应用程序的版本)，例如:

I have an array of strings (of an app's versions) randomly ordered like:

var arrayOfStrings = ["2.12.5", "2.12.10", "2.2", "2.11.8"]

排序后的数组应为 ["2.2", "2.12.10", "2.12.5", "2.11.8"](按最近排序).我正在尝试对其进行排序.

The sorted array should be ["2.2", "2.12.10", "2.12.5", "2.11.8"] (ordered by most recent). I am trying to sort it.

我的错，排序后的数组实际上应该是 ["2.12.10", "2.12.5", "2.11.8", "2.2"].使用上面的解决方案.

My bad, the sorted array should actually be ["2.12.10", "2.12.5", "2.11.8", "2.2"]. Use the solution above.

//Compare by string
array.sortInPlace({ //This returns ["2.2", "2.12.5", "2.12.10", "2.11.8"]
    $0 > $1
})

//Compare by int
array.sortInPlace({ //This returns ["2.12.10", "2.12.5", "2.11.8", "2.2"]
    Int($0.stringByReplacingOccurrencesOfString(".", withString: "")) > Int($1.stringByReplacingOccurrencesOfString(".", withString: ""))
})

这些都不能正常工作.返回正确数组的最佳方法是什么?

None of this is working properly. What is the best way to return the correct array?

推荐答案

最简单的选择是使用 compare 和 .NumericSearch:

The easiest option is to use compare with .NumericSearch:

arrayOfStrings.sortInPlace { $0.compare($1, options: .NumericSearch) == .OrderedAscending }

显然，如果您希望它按降序排列，请使用 .OrderedDescending.

Obviously, if you want it in descending order, use .OrderedDescending.

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