mySQL 查询返回资源 ID #5

mySQL query returning Resource id #5(mySQL 查询返回资源 ID #5)

问题描述

我已经搜索了可能的解决方案.我尝试过循环以及尝试 mysql_fetch_assoc 和 mysql_fetch_array 的变体，但我仍然得到资源 ID #5: 0: 错误.

I've searched about possible solutions to this. and I've tried looping as well as trying the variants of mysql_fetch_assoc and mysql_fetch_array but I'm still getting the Resource id #5: 0: error.

这是我认为会产生错误的代码.

Here's my code which I think generates the error.

   <?php
            mysqlc();
            $email = GetSQLValueString($_SESSION['user'], "text");
            $query = sprintf("SELECT * FROM newmember WHERE email = %s",$email);
            $res = mysql_query($query) or die('Query failed: ' . mysql_error() . "<br />
$sql");
            $row = mysql_fetch_assoc($res);
    ?>  

推荐答案

"Resource id #5: 0" 不是错误.这意味着您尝试 echo $res 而不是尝试使用 $row 变量，例如 $row[column] 用于 fetch_assoc，$row[0] 用于 fetch_row, fetch_array 中的一个/两个.

"Resource id #5: 0" is not an error. It means that you tried to echo $res instead of trying to use the $row variable, such as $row[column] for fetch_assoc, $row[0] for fetch_row, either/both for fetch_array.

其他答案解释mysql_fetch_*的使用

The other answers explain the use of mysql_fetch_*

此外，不推荐使用 mysql_*.您应该改用 mysqli_* 或 PDO 函数.

Also, mysql_* is deprecated. You should use mysqli_* or PDO functions instead.

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