问题描述

我正在编写一个生成一些 Excel 文档的脚本，我需要将一个数字转换为其等效的列名.例如:

I'm working on a script that generate some Excel documents and I need to convert a number into its column name equivalent. For example:

1 => A
2 => B
27 => AA
28 => AB
14558 => UMX

我已经编写了一个算法来这样做，但我想知道是否有更简单或更快的方法来做到这一点:

I have already written an algorithm to do so, but I'd like to know whether are simpler or faster ways to do it:

function numberToColumnName($number){
    $abc = "ABCDEFGHIJKLMNOPQRSTUVWXYZ";
    $abc_len = strlen($abc);

    $result_len = 1; // how much characters the column's name will have
    $pow = 0;
    while( ( $pow += pow($abc_len, $result_len) ) < $number ){
        $result_len++;
    }

    $result = "";
    $next = false;
    // add each character to the result...
    for($i = 1; $i<=$result_len; $i++){
        $index = ($number % $abc_len) - 1; // calculate the module

        // sometimes the index should be decreased by 1
        if( $next || $next = false ){
            $index--;
        }

        // this is the point that will be calculated in the next iteration
        $number = floor($number / strlen($abc));

        // if the index is negative, convert it to positive
        if( $next = ($index < 0) ) {
            $index = $abc_len + $index;
        }

        $result = $abc[$index].$result; // concatenate the letter
    }
    return $result;
}

你知道更好的方法吗?也许是为了让它更简单?还是性能改进?

Do you know a better way to do it? Maybe something to keep it simpler? or a performance improvement?

ircmaxell 的实现效果很好.但是，我要添加这个简短的内容:

ircmaxell's implementation works pretty fine. But, I'm going to add this nice short one:

function num2alpha($n)
{
    for($r = ""; $n >= 0; $n = intval($n / 26) - 1)
        $r = chr($n%26 + 0x41) . $r;
    return $r;
}

推荐答案

这是一个很好的简单递归函数(基于零索引数，意思是 0 == A、1 == B 等)...

Here's a nice simple recursive function (Based on zero indexed numbers, meaning 0 == A, 1 == B, etc)...

function getNameFromNumber($num) {
    $numeric = $num % 26;
    $letter = chr(65 + $numeric);
    $num2 = intval($num / 26);
    if ($num2 > 0) {
        return getNameFromNumber($num2 - 1) . $letter;
    } else {
        return $letter;
    }
}

如果你想要一个索引(1 == A，等等):

And if you want it one indexed (1 == A, etc):

function getNameFromNumber($num) {
    $numeric = ($num - 1) % 26;
    $letter = chr(65 + $numeric);
    $num2 = intval(($num - 1) / 26);
    if ($num2 > 0) {
        return getNameFromNumber($num2) . $letter;
    } else {
        return $letter;
    }
}

使用从 0 到 10000 的数字进行测试...

Tested with numbers from 0 to 10000...

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