在php中没有对象实例化的情况下调用类方法(带构造函数)

问题描述

我已经查看并尝试过，但我找不到答案.

Ive looked and tried but I can't find an answer.

在 PHP 中，是否可以在不将其实例化为对象的情况下调用类的成员函数(当该类需要构造函数来接收参数时)?

In PHP, is it possible to call a class' member function (when that class requires a constructor to receive parameters) without instantiating it as an object?

代码示例(给出错误):

A code example (which gives errors):

<?php

class Test {
    private $end="";

    function __construct($value) {
        $this->end=$value;
    }

    public function alert($value) {
        echo $value." ".$this->end;
    }
}

//this works:
$example=new Test("world");
$example->alert("hello");

//this does not work:
echo Test("world")::alert("hello");

?>

推荐答案

不幸的是 PHP 不支持这样做，但你是一个有创造力和外观的人 :D

Unfortunately PHP doesn't have support to do this, but you are a creative and look guy :D

您可以使用工厂"，示例:

You can use an "factory", sample:

<?php

class Foo
{
   private $__aaa = null;

   public function __construct($aaa)
   {
      $this->__aaa = $aaa;
   }

   public static function factory($aaa)
   {
      return new Foo($aaa);
   }

   public function doX()
   {
      return $this->__aaa * 2;
   }
}

Foo::factory(10)->doX();   // outputs 20

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