问题描述
如果我尝试声明一个属性，如下所示:
public $quantity = 9;...它不起作用，因为它不被视为属性"，而只是模型类的属性.不仅如此，我还阻止了对实际真实存在的数量"属性的访问.
那我该怎么办?
这就是我现在正在做的:
protected $defaults = array('数量' =>9、);公共函数 __construct(array $attributes = array()){$this->setRawAttributes($this->defaults, true);parent::__construct($attributes);}我建议将此作为 PR，因此我们不需要在每个模型中都声明此构造函数，并且只需在我们的模型中声明 $defaults 数组即可轻松应用...<小时>
更新:
正如 cmfolio 所指出的，实际的答案很简单:
只需覆盖 $attributes 属性即可！像这样:
protected $attributes = array('数量' =>9、);在此处讨论了该问题.
If I try declaring a property, like this:
public $quantity = 9;
...it doesn't work, because it is not considered an "attribute", but merely a property of the model class. Not only this, but also I am blocking access to the actually real and existent "quantity" attribute.
What should I do, then?
This is what I'm doing now:
protected $defaults = array(
'quantity' => 9,
);
public function __construct(array $attributes = array())
{
$this->setRawAttributes($this->defaults, true);
parent::__construct($attributes);
}
I will suggest this as a PR so we don't need to declare this constructor at every Model, and can easily apply by simply declaring the $defaults array in our models...
UPDATE:
As pointed by cmfolio, the actual ANSWER is quite simple:
Just override the $attributes property! Like this:
protected $attributes = array(
'quantity' => 9,
);
The issue was discussed here.
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