如何从数据库中的mysqli输入中搜索值

本文介绍了如何从数据库中的mysqli输入中搜索值的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着跟版网的小编来一起学习吧！

问题描述

我想在使用值的第一个字符时显示我的数据库值.让我用我的网站来描述它我有一个带有主页输入的网站，其中用户键入输入作为火车号.我需要那个用户类型的火车号.他从我存储的数据库中获得了火车名称.

解决方案

检查此代码.我认为它会对您有所帮助

<头><meta http-equiv="Content-Type" content="text/html; charset=utf-8"><title>PHP、jQuery搜索演示</title><link rel="stylesheet" type="text/css" href="my.css"><script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.3.2/jquery.min.js"></script><script type="text/javascript">$(document).ready(function () {$("输入").keyup(function () {$('#results').html('');var searchString = $("#search_box").val();var data = 'search_text=' + searchString;如果(搜索字符串){$.ajax({类型:POST"，网址:'search.php'，数据:数据，数据类型:'文本'，异步:假，缓存:假，成功:功能(结果){$('#results').html(result);//window.location.reload();}});}});});<身体><div id="容器"><div style="margin:20px auto; text-align: center;"><form method="post" action="do_search.php"><input type="text" name="search" id="search_box" class='search_box'/><input type="submit" value="Search" class="search_button"/><br/></表单>

<div><div id="searchresults">搜索结果:</div><ul id="results" class="update">

connect_error){die("连接失败:" . $conn->connect_error);}$sql = "从 yourtable_name WHERE match_text LIKE '%$searchquery%' 中选择字段 1，字段 2";$result = $conn->query($sql);如果($result->num_rows>0){//输出每一行的数据while($row = $result->fetch_assoc()) {回声-名称:".$row["filed1"]."".$row["field2"]."<br>";}} 别的 {echo "0 结果";}$conn->close();?>

<html> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8"> <title>PHP, jQuery search demo</title> <link rel="stylesheet" type="text/css" href="my.css"> <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.3.2/jquery.min.js"></script> <script type="text/javascript"> $(document).ready(function () { $("input").keyup(function () { $('#results').html(''); var searchString = $("#search_box").val(); var data = 'search_text=' + searchString; if (searchString) { $.ajax({ type: "POST", url: 'search.php', data: data, dataType: 'text', async: false, cache: false, success: function (result) { $('#results').html(result); //window.location.reload(); } }); } }); }); </script> </head> <body> <div id="container"> <div style="margin:20px auto; text-align: center;"> <form method="post" action="do_search.php"> <input type="text" name="search" id="search_box" class='search_box'/> <input type="submit" value="Search" class="search_button"/><br/> </form> </div> <div> <div id="searchresults">Search results :</div> <ul id="results" class="update"> </ul> </div> </div> </body> </html>

<?php $servername = "localhost"; $username = "db_username"; $password = "db_password"; $dbname = "your_db_name"; $searchquery = trim($_POST['search_text']); //input for search // Create connection $conn = new mysqli($servername, $username, $password, $dbname); // Check connection if ($conn->connect_error) { die("Connection failed: " . $conn->connect_error); } $sql = "SELECT filed1, field2 FROM yourtable_name WHERE match_text LIKE '%$searchquery%'"; $result = $conn->query($sql); if ($result->num_rows > 0) { // output data of each row while($row = $result->fetch_assoc()) { echo " - Name: " . $row["filed1"]. " " . $row["field2"]. "<br>"; } } else { echo "0 results"; } $conn->close(); ?>

如何从数据库中的mysqli输入中搜索值

问题描述

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