问题描述
这些是我选择的对角线点的坐标,选择的点越多就会越多.
These are my coordinates of Selected diagonal points, will be more when selected points are more.
1: 25.312063043186914 2: 55.30672073364258
1: 25.24096949112138 2: 55.40525436401367
1: 25.224509592006314 2: 55.3462028503418
1: 25.22513076073063 2: 55.281314849853516
1: 25.27822894908031 2: 55.25899887084961
下面是我当前的 mysql 查询在选定的对角线之间没有给我完美的结果.有帮助吗??
below is my current mysql query not giving me perfect result between selected diagonal.any help??
SELECT
*
FROM
tbl_custom
WHERE latitude <= 25.312063043186914
AND latitude >= 25.224509592006314
AND longitude <= 55.40525436401367
AND longitude >= 55.25899887084961
推荐答案
要消除边界框查询内但不在多边形内的点,您需要使用 多边形中的点 算法.
To eliminate the points within your bounding box query but not within polygon you require to use Point in Polygon algorithm.
最简单的方法是使用数组中的坐标.这些可用于查找查询的最大和最小坐标以及 pointInPolygon() 函数的参数.
The easiest way to do this is to have the coordinates in arrays. These can be used to find max and min coordinates for the query and for parameters for pointInPolygon() function.
function pointInPolygon(polySides,polyX,polyY,x,y) {
var j = polySides-1 ;
oddNodes = 0;
for (i=0; i<polySides; i++) {
if (polyY[i]<y && polyY[j]>=y || polyY[j]<y && polyY[i]>=y) {
if (polyX[i]+(y-polyY[i])/(polyY[j]-polyY[i])*(polyX[j]-polyX[i])<x) {
oddNodes=!oddNodes;
}
}
j=i; }
return oddNodes;
}
在您的地图代码中使用 jQuery getJSON()
In your Map code using jQuery getJSON()
var polySides = 4;//number of points in polygon
//horizontal Latitude coordinates of polygon
var polyLat = new Array();
polyLat[0] = 51.5;
polyLat[1] = 51.5;
polyLat[2] = 52.5;
polyLat[3] = 53;
polyLat[4] = 51.5;//First point repeated to close polygon
//vertical Longitude coordinates of polygon
var polyLng = new Array();
polyLng[0] = 0.5;
polyLng[1] = -1.9;
polyLng[2] = -1;
polyLng[3] = 0.6;
polyLng[4] = 0.5;
//Coordinates for bounding box
var maxLat = Math.max.apply(null,polyLat);
var minLat = Math.min.apply(null,polyLat);
var maxLng = Math.max.apply(null,polyLng);
var minLng = Math.min.apply(null,polyLng);
//Using jQuery
var url = "yourFile .php";
url +="?maxLat="+maxLat +"&minLat="+minLat +"&maxLng="+maxLng +"&minLng="+minLng;
$.getJSON(url,function(data) {
$.each(data.marker,function(i,dat){
if (pointInPolygon(polySides,polyLat,polyLng,dat.lat,dat.lng)){
var latlng = new google.maps.LatLng(dat.lat,dat.lng);
addMarker(latlng,dat.name);
bounds.extend(latlng);
}
});
map.fitBounds(bounds);
});
使用边界框和多边形中的点获得的地图.
Map obtained using Bounding Box and Point in Polygon.
这篇关于如何在mysql查询中找到所选对角线区域之间的准确数据的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持跟版网!



大气响应式网络建站服务公司织梦模板
高端大气html5设计公司网站源码
织梦dede网页模板下载素材销售下载站平台(带会员中心带筛选)
财税代理公司注册代理记账网站织梦模板(带手机端)
成人高考自考在职研究生教育机构网站源码(带手机端)
高端HTML5响应式企业集团通用类网站织梦模板(自适应手机端)