问题描述

我有一段这样的代码:

$conn = new mysqli($host, $username, $passwd, $dbname);

...

$stmt = $conn->prepare('SELECT ...');
$stmt->bind_param(...);
$stmt->execute();
$stmt->bind_result(...);
while($stmt->fetch())
{
    // do something here
}
$stmt->close();

...

// do something more here that has absolutely nothing to do with $stmt

这很好用.我得到了预期的结果，没有错误或任何不应该发生的事情.

This works perfectly fine. I get the results I expected, there are no errors or anything that is not supposed to happen.

但是如果我将断点(Xdebug 2.2.5/2.2.6/2.2.8/2.3.2 和 PHP 5.5.3/5.5.15/5.6.0/5.6.6/5.6.10)设置为一行之后 $stmt->close();，我收到很多警告，比如

But if I set a break point (Xdebug 2.2.5 / 2.2.6 / 2.2.8 / 2.3.2 and PHP 5.5.3 / 5.5.15 / 5.6.0 / 5.6.6 / 5.6.10) to a line after $stmt->close();, I get many warnings like

尚未允许访问属性

或

无法获取 mysqli_stmt

Couldn't fetch mysqli_stmt

我以为我错过了关闭另一个 mysqli 语句，但我得到了所有结果.我的代码似乎没有问题...

I thought I missed to close another mysqli statement, but I get all results. There seems to be just no problem in my code...

有没有办法摆脱这种错误警告?

Is there a way to get rid of this wrong warnings?

更新:这个问题在 PHP 7.0.1/Xdebug 2.4.0 RC3 中仍然存在.

Update: This problem still exist in PHP 7.0.1 / Xdebug 2.4.0 RC3.

推荐答案

有一些类似的问题报告
http://bugs.xdebug.org/view.php?id=900
https://bugs.php.net/bug.php?id=60778

摆脱此消息的一种方法是添加

One way to get rid of this messages is to add

unset($stmt);

在关闭语句之后和断点之前.如果这没有帮助，您还应该添加

after closing the statement and before the breakpoint. If this does not help, you should also add

unset($connection);

在@Martin 在评论中提到关闭连接之后.

after closing the connection as mentioned by @Martin in the comments.

这本身并不能解决问题，而是让您继续工作，直到这可能会在一段时间内得到解决.

This does not solve the problem itself, but let you go on with your work until this may be fixed some time.

编辑:现在还有一个报告的问题 :)

编辑:据报道，这似乎是 MySQLi 驱动程序中的一个错误 此处.

EDIT: This seems to be a bug in the MySQLi driver as reported here.

EDIT:如果您使用 PDO，看起来这个错误不会出现.所以这可能是切换到 PDO 的另一个原因.

EDIT: Looks like this bug does not appear if you use PDO. So this is maybe an other reason to switch to PDO.

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