带有“WHERE ... IN"的 PDO查询

问题描述

我正在修改一些 PHP 代码以使用 PDO 进行数据库访问，但我遇到了WHERE... IN"查询的问题.

I'm reworking some PHP code to use PDO for the database access, but I'm running into a problem with a "WHERE... IN" query.

我正在尝试从数据库中删除一些内容，基于表单上的哪些项目被检查.列表的长度和内容会有所不同，但对于这个例子，想象一下:

I'm trying to delete some things from a database, based on which items on a form are checked. The length and content of the list will vary, but for this example, imagine that it's this:

$idlist = '260,201,221,216,217,169,210,212,213';

然后查询看起来像这样:

Then the query looks like this:

$query = "DELETE from `foo` WHERE `id` IN (:idlist)";
$st = $db->prepare($query);
$st->execute(array(':idlist' => $idlist));

当我这样做时，只会删除第一个 ID.(我假设它会抛出逗号及其后的所有内容.)

When I do this, only the first ID is deleted. (I assume it throws out the comma and everything after it.)

我也试过把 $idlist 变成一个数组，但它并没有删除任何东西.

I've also tried making $idlist an array, but then it doesn't delete anything.

在 PDO 准备好的语句中使用项目列表的正确方法是什么?

推荐答案

由于您无法将值(数字)与控制流逻辑(逗号)与准备好的语句混合使用，因此每个值需要一个占位符.

Since you can't mix Values (the Numbers) with control flow logic (the commas) with prepared statements you need one placeholder per Value.

$idlist = array('260','201','221','216','217','169','210','212','213');

$questionmarks = str_repeat("?,", count($idlist)-1) . "?";

$stmt = $dbh->prepare("DELETE FROM `foo` WHERE `id` IN ($questionmarks)");

并循环绑定参数.

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